我有一个 python 列表作为字符串，我想将它打印出来作为间隔和顺序

Question

I have a python list and i want to print them in an sequential order and spaced between them

x = "hello world"
>>> x[2:10]  # this prints from 'l' to 'd' allway

>>> x[2:10:2]  # this prints from 'l' to 'd' in the order of two,
'lowr'

how can i print it like 'lowr ', putting a space character between them without a loop? So it would look like 'low-r'

Answer 1

Check out Python's str.join() function. It lets you join any iterable whilst inserting whatever you put in between the quotes "" in .join() .

Like so:

x = "hello world"

" ".join(x[2:10:2])

Answer 2

Just join the characters in the list with a single space, or with a - , as you feel like. This uses a join which gives you a string stitched together from the elements of the list by the given separator

x = "hello world"
print(' '.join(x[2:10:2]))
#l o w r
print('-'.join(x[2:10:2]))
#l-o-w-r

Answer 3

Strings have a .join() method which will join together the elements of that iterable with the string you give in the middle. For example

>>> x = 'hello world'
>>> sep = ' '  # your separator is a space
>>> sep.join(x[2:10:2])
'l o w r'

Answer 4

Not sure what you mean by without a loop, but you could do the following:

x = "hello world"
' '.join(y for y in x[2:10:2])