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调整图像Python Tkinter的大小

[英]Resizing image Python Tkinter

Hello I am having issues with resizing my picture. 你好,我在调整图片大小时遇到​​问题。 I am trying to resize the image to fit the blue drawing. 我正在尝试调整图像大小以适应蓝色绘图。 However the way I am doing it, returns an error. 但是我这样做的方式会返回错误。

File "gui.py", line 42, in fileDialog
self.display = Label(image=self.photo.resize((800, 600),Image.ANTIALIAS))
AttributeError: 'PhotoImage' object has no attribute 'resize

I am just testing it to see if it fits by doing 800,600 I really don't know. 我只是测试它是否适合做800,600我真的不知道。

def fileDialog(self):
    self.filename = filedialog.askopenfilename(title="Select")
    self.label = ttk.Label(self.labelFrame, text="")
    self.label.grid(column=1, row=2)
    self.label.configure(text=self.filename)
    self.photo= ImageTk.PhotoImage(file = self.filename)
    self.display = Label(image=self.photo.resize((800, 600),Image.ANTIALIAS))
    self.display.grid(row=0)

在蓝色图纸中插入图像

Is there something that I am doing incorrectly? 有什么我做错了吗? Please advise. 请指教。

You need to resize the image, not the photoimage. 您需要调整图像大小,而不是照片图像。

import tkinter as tk
from PIL import Image, ImageTk

filename = 'bell.jpg'
img = Image.open(filename)
resized_img = img.resize((200, 100))

root = tk.Tk()
root.photoimg = ImageTk.PhotoImage(resized_img)
labelimage = tk.Label(root, image=root.photoimg)
labelimage.pack()

在此输入图像描述

To address the new question, you do not have to know the filename at the time of label creation. 要解决新问题,您无需在创建标签时知道文件名。 The following code produces the same result: 以下代码生成相同的结果:

import tkinter as tk
from PIL import Image, ImageTk

root = tk.Tk()
labelimage = tk.Label(root)
labelimage.pack()

filename = 'bell.jpg'
img = Image.open(filename)
resized_img = img.resize((200, 100))
root.photoimg = ImageTk.PhotoImage(resized_img)
labelimage.configure(image=root.photoimg)

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