C＃在控制台应用程序中构建Visual Studio项目

Question

I am trying to build my visual studio sln project in code. I am calling the vs 2017 command prompt then trying to send the command Msbuild. I am getting the following error:

“[ERROR:parse_cmd.bat] Invalid command line argument: 'msbuild'. Argument will be ignored. [ERROR:parse_cmd.bat] Invalid command line argument: 'projectName.sln'. Argument will be ignored.”

Failing at the line buildInfo.Arguments = "msbuild project.sln";

Process cmd = new Process();
    try
    {
        ProcessStartInfo buildInfo = new ProcessStartInfo();
        buildInfo.CreateNoWindow = false;
        buildInfo.RedirectStandardError = true;
        buildInfo.RedirectStandardOutput = true;
        buildInfo.RedirectStandardInput = true;
        buildInfo.UseShellExecute = false;
        buildInfo.FileName = @"C:\Program Files (x86)\Microsoft Visual Studio\2017\Professional\Common7\Tools\VsDevCmd.bat";
        buildInfo.WorkingDirectory = @"directoryToProject";
        buildInfo.Arguments = "msbuild project.sln";

        cmd.StartInfo = buildInfo;

        cmd.Start();
        string stderr_str = cmd.StandardError.ReadToEnd();
        string stdout_str = cmd.StandardOutput.ReadToEnd();

        Console.WriteLine(stderr_str);
        Console.WriteLine(stdout_str);

        cmd.WaitForExit();
    }
    catch (Exception e)
    {
        Console.WriteLine(e);
    }
    finally
    {
        cmd.Close();
      Console.WriteLine("Built the project");
    }
}

I expect it to build the sln project.

Answer 1

如果您要做的只是构建，我建议将C:\\Program Files (x86)\\Microsoft Visual Studio\\2017\\Professional\\Common7\\Tools\\VsDevCmd.bat更改为MSBuild可执行文件的路径，它应该像C:\\Program Files (x86)\\Microsoft Visual Studio\\2017\\Professional\\MSBuild\\15.0\\Bin\\amd64一样C:\\Program Files (x86)\\Microsoft Visual Studio\\2017\\Professional\\MSBuild\\15.0\\Bin\\amd64然后它应该构建。