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我想根据索引合并两个关联数组

[英]I want to merge two assoiciative arrays based on index

I have two arrays with indexes 1 to 10 and then I have to make it merge based on the index.我有两个索引为 1 到 10 的数组,然后我必须根据索引将其合并。 So only some employee have to be added Salary.所以只有一些员工必须添加薪水。

I have tried using array_merge() but the output is not merging.我试过使用array_merge()但输出没有合并。 I am not able to get proper output.我无法获得正确的输出。 Output coming is only the employeeSalary Array.输出只是employeeSalary数组。 Why is it so?为什么会这样?

$employee = array
(
0=>
    array("employee_id"=>1, "firstName"=>"Zahir", "lastName"=>"Alam", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"
        ,"Head"=>
            array("Id"=>3 , "Name"=>"Sourasis Roy")
    )
,
1=>
    array("employee_id"=>2, "firstName"=>"Amith", "lastName"=>"Manniken", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"
        ,"Head"=>
            array("Id"=>3 , "Name"=>"Sourasis Roy")
    )
,
2=>
    array("employee_id"=>3, "firstName"=>"Sourasis", "lastName"=>"Roy", "Age"=>28, "Company"=>"Switchme", "Role"=>"CTO")
,
3=>
    array("employee_id"=>4, "firstName"=>"Aditya", "lastName"=>"Mishra", "Age"=>29, "Company"=>"Switchme", "Department"=>"Tech", "Role"=>"CEO")
,
4=>
    array("employee_id"=>5, "firstName"=>"Priti", "lastName"=>"Lata", "Age"=>24, "Company"=>"Switchme", "Role"=>"HR")
,
5=>
    array("employee_id"=>6, "firstName"=>"Sumita", "lastName"=>"Nath", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm")
,
6=>
    array("employee_id"=>7, "firstName"=>"Tarini", "lastName"=>"Khanna", "Age"=>22, "Company"=>"Switchme", "Role"=>"Content Writer")
,
7=>
    array("employee_id"=>8, "firstName"=>"Abhisek", "lastName"=>"Soni", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm","Head"=>array("Id"=>5 , "Name"=>"Sumita Nath")
    )
,
8=>
    array("employee_id"=>9, "firstName"=>"Ankit", "lastName"=>"Pump", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm"
        ,"Head"=>
            array("Id"=>5 , "Name"=>"Sumita Nath")
    )
,
9=>
    array("employee_id"=>10, "firstName"=>"Pogo", "lastName"=>"Laal", "Age"=>23, "Company"=>"Switchme", "Role"=>"Designer")
,
10=>
    array("employee_id"=>11, "firstName"=>"Sabina", "lastName"=>"Sekh", "Age"=>28, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm")
,
11=>
    array("employee_id"=>12, "firstName"=>"Sanjay", "lastName"=>"Poudal", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm"
        ,"Head"=>
            array("Id"=>10 , "Name"=>"Sabina Sekh")
    )
,
);

$employee_salary = array
(
7=>
    array("employee_id"=>7, "salary"=>"55,000"
    )
,
2=>
    array("employee_id"=>2, "salary"=>"60,000"
    )
,
9=>
    array("employee_id"=>9, "salary"=>"50,000"
    )
,
10=>
    array("employee_id"=>10, "salary"=>"30,000"
    )
,
);

$ar= array();
for($j=0;$j<count($employee);$j++)
{
    error_reporting(0);
    if($employee[$j]=$employee_salary[$j])
    {
        $ar=$employee[$j]+$employee_salary[$j];
        print_r($ar);
        echo "<br>";
    }
    error_reporting(0);
}

AS said by chris white you forgot to add one more = for compare.and check array index is set or not in second array of employee_salary using isset() .正如克里斯·怀特所说,您忘记再添加一个 = 用于比较。并使用isset()检查是否在 employee_salary 的第二个数组中设置了数组索引。 like if($employee[$j]==isset($employee_salary[$j]))比如if($employee[$j]==isset($employee_salary[$j]))

$employee = array
(
0=>
    array("employee_id"=>1, "firstName"=>"Zahir", "lastName"=>"Alam", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"
        ,"Head"=>
            array("Id"=>3 , "Name"=>"Sourasis Roy")
    )
,
1=>
    array("employee_id"=>2, "firstName"=>"Amith", "lastName"=>"Manniken", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"
        ,"Head"=>
            array("Id"=>3 , "Name"=>"Sourasis Roy")
    )
,
2=>
    array("employee_id"=>3, "firstName"=>"Sourasis", "lastName"=>"Roy", "Age"=>28, "Company"=>"Switchme", "Role"=>"CTO")
,
3=>
    array("employee_id"=>4, "firstName"=>"Aditya", "lastName"=>"Mishra", "Age"=>29, "Company"=>"Switchme", "Department"=>"Tech", "Role"=>"CEO")
,
4=>
    array("employee_id"=>5, "firstName"=>"Priti", "lastName"=>"Lata", "Age"=>24, "Company"=>"Switchme", "Role"=>"HR")
,
5=>
    array("employee_id"=>6, "firstName"=>"Sumita", "lastName"=>"Nath", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm")
,
6=>
    array("employee_id"=>7, "firstName"=>"Tarini", "lastName"=>"Khanna", "Age"=>22, "Company"=>"Switchme", "Role"=>"Content Writer")
,
7=>
    array("employee_id"=>8, "firstName"=>"Abhisek", "lastName"=>"Soni", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm","Head"=>array("Id"=>5 , "Name"=>"Sumita Nath")
    )
,
8=>
    array("employee_id"=>9, "firstName"=>"Ankit", "lastName"=>"Pump", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm"
        ,"Head"=>
            array("Id"=>5 , "Name"=>"Sumita Nath")
    )
,
9=>
    array("employee_id"=>10, "firstName"=>"Pogo", "lastName"=>"Laal", "Age"=>23, "Company"=>"Switchme", "Role"=>"Designer")
,
10=>
    array("employee_id"=>11, "firstName"=>"Sabina", "lastName"=>"Sekh", "Age"=>28, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm")
,
11=>
    array("employee_id"=>12, "firstName"=>"Sanjay", "lastName"=>"Poudal", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm"
        ,"Head"=>
            array("Id"=>10 , "Name"=>"Sabina Sekh")
    )
,
);

$employee_salary = array
(
7=>
    array("employee_id"=>7, "salary"=>"55,000"
    )
,
2=>
    array("employee_id"=>2, "salary"=>"60,000"
    )
,
9=>
    array("employee_id"=>9, "salary"=>"50,000"
    )
,
10=>
    array("employee_id"=>10, "salary"=>"30,000"
    )
,
);

$ar= array();
for($j=0;$j<count($employee);$j++)
{

    error_reporting(0);
    if($employee[$j]==isset($employee_salary[$j]))
    {
        $ar=$employee[$j]+$employee_salary[$j];

        print_r($ar);
        echo "<br>";
    }
    error_reporting(0);
}

Working Example: http://phpfiddle.org/main/code/dbi8-4krn工作示例:http: //phpfiddle.org/main/code/dbi8-4krn

Try out the following solution, with the values of arrays $employee and $employee_salary as given in the question.尝试以下解决方案,使用问题中给出的数组$employee$employee_salary的值。

$ar= array();

foreach($employee as $j => $v){
    $id = $v['employee_id'];
    foreach($employee_salary as $i => $u){
     $id_s = $u['employee_id'] ;

     if($id == $id_s){
       $ar = $employee[$j] + $employee_salary[$i];
       print_r($ar);
       echo "<br>";
     }
    }
}

I think there will be an easy solution as well.我认为也会有一个简单的解决方案。 Because you already made employee_salary array with the id key.因为您已经使用 id 键创建了 employee_salary 数组。 So it will be like this.所以就会这样。

Foreach($employee as $key=> $value)
{ 
     $employee[$key]['salary'] = $employee_salary[$value['employee_id']]['salary'];

 }
 Print_r($employee);die;

I think this will help you out.我想这会帮助你。 Thanks谢谢

That should do那应该做

    $ar= array();
    for($j=0;$j<count($employee);$j++)
    {
        $ar[$j]=$employee[$j];
        if(isset($employee_salary[$employee[$j]["employee_id"]]) && $employee_salary[$employee[$j]["employee_id"]]['employee_id'] == $employee[$j]["employee_id"] ){
            $ar[$j]=array_merge($employee[$j],$employee_salary[$employee[$j]["employee_id"]]);
        }
    }

Pay attention to the array keys.注意数组键。

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