使用正则表达式跳过结果

Question

I want to filter out results form a API and want to exclude certain results form showing up for example:

LEGACY-NA-XboxOfficialServer219
EU-PVP-XboxOfficial-TheIslanSmallTribes219
EU-PVP-XboxOfficial-TheIsland219

I want the last result. So I put a Negative look behind for the smalltribes part but now need something to identify if its LEGACY or not and to skip that result if it is

What i have so far:

re.search(r"[a-zA-Z](?<!SmallTribes)" + str(number) + r"$", x['Name']):

Im trying to get it to only display

EU-PVP-XboxOfficial-TheIsland219

Answer 1

You may use

^(?!LEGACY).*[a-zA-Z](?<!SmallTribes)219$

See the regex demo .

Details

• ^ - start of string
• (?!LEGACY) - no LEGACY substring at the start is allowed
• .* - any 0+ chars other than line break chars, as many as possible
• [a-zA-Z] - a letter
• (?<!SmallTribes) - no SmallTribes substring right before...
• 219$ - the 219 number at the end of the string.

In Python:

re.search(r"^(?!LEGACY).*[a-zA-Z](?<!SmallTribes){}$".format(number), x['Name']):

See the Python demo online :

import re
strs = ['LEGACY-NA-XboxOfficialServer219',
'EU-PVP-XboxOfficial-TheIslanSmallTribes219',
'EU-PVP-XboxOfficial-TheIsland219']
number = 219
rx = re.compile(r"^(?!LEGACY).*[a-zA-Z](?<!SmallTribes){}$".format(number))
for s in strs:
    if re.search(rx, s):
        print(s)
# => EU-PVP-XboxOfficial-TheIsland219