[英]Powershell regex to grab data between second set of double quotes
I have a dataset like the below, I've been trying to use split to get the second column of data. 我有一个像下面这样的数据集,我一直试图使用split来获取第二列数据。 Can this be done with a regex?
可以用正则表达式完成吗? I just need the data in the second column, the unc paths.
我只需要第二列中的数据,即unc路径。
"\app\DATA\8161ST1\201901\20190111\2562233\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562233\*.*"
"\app\DATA\8161ST1\201901\20190111\2562234\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562234\*.*"
"\app\DATA\8161ST1\201901\20190111\2562235\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562235\*.*"
A conceptually simple solution: 一个概念上简单的解决方案:
# Array of input lines, such as would be returned by Get-Content
$lines = @'
"\app\DATA\8161ST1\201901\20190111\2562233\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562233\*.*"
"\app\DATA\8161ST1\201901\20190111\2562234\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562234\*.*"
"\app\DATA\8161ST1\201901\20190111\2562235\" "\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562235\*.*"
'@ -split [Environment]::NewLine
# Extract the content of the last "..."-enclosed token from each line.
$lines | ForEach-Object { ($_ -split '"')[-2] }
The above yields: 以上收益:
\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562233\*.*
\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562234\*.*
\\server\i\Run\client\AHFC\201901\app\DATA\8161ST1\201901\20190111\2562235\*.*
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