正则表达式替换字符串的第一个索引处除减号“-”以外的所有无效字符

Question

I'm using the following regex to replace all invalid characters which exist in the decimal number string:

final String REGEX_REPLACE_INVALID_DECIMAL_NUMBER_CHARACTERS = "\\D*(\\d+\\.?\\d*)\\D*";

This is my test code:

    String[] inputs = {
        "0a", // -> 0
        "a0a.0", // -> 0.0
        "b0a.t1c", // -> 0.1
        "-a0b.c1d", // -> -0.1
        "-#0.t12[3]", // -> -0.123
        "-123.[1]2_3", // -> -123.123
    };

    final String REPLACE_INVALID_DECIMAL_NUMBER_CHARACTERS = "\\D*(\\d+\\.?\\d*)\\D*";
    for (String input : inputs) {
        String replaceInvalidDecimalNumberCharacters = input.replaceAll(REPLACE_INVALID_DECIMAL_NUMBER_CHARACTERS, "$1");
        System.out.println("input: " + input +
                "\n\treplaceInvalidDecimalNumberCharacters: " + replaceInvalidDecimalNumberCharacters);
    }

Currently my regex, replaces all invalid characters even decimal poinit and minus at first index of a string.

How can I exclude removing minus and decimal point?

This is my test output:

input: 0a   replaceInvalidDecimalNumberCharacters: 0
input: a0a.0    replaceInvalidDecimalNumberCharacters: 00
input: b0a.t1c  replaceInvalidDecimalNumberCharacters: 01
input: -a0b.c1d replaceInvalidDecimalNumberCharacters: 01
input: -#0.t12[3]   replaceInvalidDecimalNumberCharacters: 0.123
input: -123.[1]2_3  replaceInvalidDecimalNumberCharacters: 123.123

Answer 1

I suggest proceeding with regex using two steps. First, strip off all irrelevant characters from the input string. Then, use another regex to check if what remains after the first replacement be a valid number:

String input = "-123.[1]2_3";
input = input.replaceAll("[^0-9.-]+", "");
if (input.matches("-?\\d+(?:\\.\\d+)?")) {
    System.out.println("Found a valid number: " + input);
}
else {
    System.out.println("Input is invalid");
}