Python：在一条语句中打印列表中的所有项目

Question

My current code loops through the list and prints items i and i+1 next to each other. However, this results in code like:

for i in list:
    print(str(i) + ': ' + str(i+1))

This code works to print each item, but for project-related reasons they all need to be in one print statement, which would, if done manually, appear as:

print(str(i) + ': ' + str(i+1) + '\n' + str(i+2) + ': ' + str(i+3) + '\n'...)

Which is absurd, and also does not use iteration to loop through the list, meaning it would have to be added to for each item in the list.

Therefore, my question is, how could this be done with recursion in this manner, where items i and i+1 are printed, then items i+2 and i+3 on the next line in the same statement, and so on?

To elaborate on 'project-related reasons': The project involves the Discord module, and it needs to export the information as one message sent in the channel. This means I cannot iterate through each and print it, as that would send a new message for each item in the list.

Answer 1

First of all, try to not use list as a variable name! Secondly, you can write a generator function that runs through every second item in the list arr (starting either at 0 or 1) and join this to an empty string:

arr=[1,2,3,4,5,6,7,8]
print( ''.join("{0}: {1}\n".format(i,k)  for i,k in zip(arr[0::2], arr[1::2])) )

This yields "items i and i+1 […] then items i+2 and i+3 on the next line", as requested :

1: 2
3: 4
5: 6
7: 8

Which is however different from your initial code, so perhaps you'd rather meant "items i and i+1 […], then items i+1 and i+2 on the next line :

print( ''.join("{0}: {1}\n".format(i,k)  for i,k in zip(arr[0:], arr[1:])) )

Answer 2

print(':'.join((str(i) for i in list)))

或这个

print(''.join(( str(i)+(':'if not i%2 else '\n') for n,i in enumerate(list) )))

Answer 3

Don't you want

list_value = ['a','b','c','d','e']
print('\n'.join(('{}: {}'.format(list_value[i],list_value[i+1]) for i in range(len(list_value)-1))))

Which gives:

a: b
b: c
c: d
d: e

Rather than the @user1438644 's answer of

print(':'.join((str(i) for i in list_value)))

which gives:

a:b:c:d:e

Answer 4

Something like this would store your output in one string

output = ''

odd, even = mylist[::2], mylist[1::2]

for i in range(len(even)):
    output += '{}: {}\n'.format(odd[i], even[i])
print(output)