我试图使用ajax从数据库中检索数据并填充在引导模式中的表单

Question

I need a help here when I click on the edit button on the image below i expect to see data populated on a form in a bootstrap modal window I am using jquery ajax method to populate the data in the form of 当我点击下图中的编辑按钮时，我需要一个帮助，我希望看到在引导模态窗口中的表单上填充的数据我正在使用jquery ajax方法以数据的形式填充数据

and the edit modal image 和编辑模态图像

Here is code for the home page 这是主页的代码

  <?php require_once("connect.php"); ?> <?php require_once("fetch.php"); ?> <?php require_once("select.php"); ?> <?php require_once("process.php"); ?> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Home</title> <link href="css/bootstrap.min.css" rel="stylesheet"> <link rel="stylesheet" href="css/style.css"> <!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries --> <!-- WARNING: Respond.js doesn't work if you view the page via file:// --> <!--[if lt IE 9]> <script src="https://oss.maxcdn.com/html5shiv/3.7.3/html5shiv.min.js"></script> <script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script> <![endif]--> </head> <body> <div class="container"> <div class="row"> <div class="col-sm-8 col-sm-offset-2"> <ul class="nav nav-pills"> <li><a href="#">Home</a></li> </ul> <button type="button" class="btn btn-primary pull-right" data-toggle="modal" data-target="#myModal">Add</button> <table class="table" id="table"> <tr> <th>S/N</th> <th>Name</th> <th>Email</th> <th>Description</th> <th>Edit</th> <th>View</th> <th>Delete</th> </tr> <?php $query = "SELECT * FROM contact"; $runQuery = mysqli_query($connect, $query); if(!$runQuery){ die("Could not run select query ".mysqli_error($connect)); } $sn = 1; while($row = mysqli_fetch_assoc($runQuery)){ ?> <tr> <td><?php echo $sn++ ?></td> <td><?php echo $row["name"] ?></td> <td><?php echo $row["email"] ?></td> <td><?php echo $row["description"] ?></td> <td> <button type="button" data-toggle="modal" data-target="#myModal" class="btn btn-warning btn-sm edit-data" id="<?php echo $row['userid'] ?>">Edit</button> </td> <td> <button type="button" data-target="#viewModal" data-toggle="modal" class="btn btn-primary btn-sm view-data" id="<?php echo $row['userid'] ?>">View</button> </td> <td> <button type="button" class="btn btn-danger btn-sm del-data" id="<?php echo $row['userid'] ?>">Danger</button> </td> </tr> <?php } ?> </table> <!-- Modal --> <div id="myModal" class="modal fade" role="dialog"> <div class="modal-dialog"> <!-- Modal content--> <div class="modal-content"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal">&times;</button> <h4 class="modal-title">Add Data</h4> </div> <div class="modal-body"> <div id="success" class="alert alert-success"></div> <form class="form" method="POST" id="insertData"> <div id="nameError" class="alert alert-danger"></div> <div class="form-group"> <label>Name</label> <input type="text" class="form-control" name="name" id="name"> </div> <div id="emailError" class="alert alert-danger"></div> <div class="form-group"> <label>Email</label> <input type="text" class="form-control" name="email" id="email"> </div> <input type="hidden" name="userid" id="contactUserId"> <div id="descriptionError" class="alert alert-danger"></div> <div class="form-group"> <label>Description</label> <textarea name="description" id="description" class="form-control"></textarea> </div> <input type="submit" class="btn btn-primary" value="Add" name="add" id="add"> </form> </div> <div class="modal-footer"> <button type="button" class="btn btn-default" data-dismiss="modal">Close</button> </div> </div> </div> </div> <div id="viewModal" class="modal fade" role="dialog"> <div class="modal-dialog"> <!-- Modal content--> <div class="modal-content"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal">&times;</button> <h4 class="modal-title">View Data</h4> </div> <div class="modal-body" id="contactDetail"> </div> <div class="modal-footer"> <button type="button" class="btn btn-default" data-dismiss="modal">Close</button> </div> </div> </div> </div> </div> </div> </div> <script src="js/jquery.js"></script> <script src="js/bootstrap.min.js"></script> <script src="js/myscript.js"></script> </body> </html>

This code is for entering and updating data in the database process.php 此代码用于输入和更新数据库process.php中的数据

<?php 
if(!empty($_POST)){

    $name = $_POST["name"];
    $email = $_POST["email"];
    $description = $_POST["description"];
    $userid = $_POST["userid"];

    if($userid != ''){
        $query = "UPDATE contact SET name = '$name', email='$email', description='$description' WHERE userid = $userid ";
        $runQuery = mysqli_query($connect, $query);
        if(!$runQuery){
            die("Could not run query ".mysqli_error($connect));
        }
    }else{
        $query = "INSERT INTO contact(name, email, description) VALUES ";
        $query .=" ('$name', '$email', '$description')";
        $runQuery = mysqli_query($connect, $query);
        if(!$runQuery){
            die("Could not run insert query ".mysqli_error($connect));
        }
    }
}

This code retrieves data from database 此代码从数据库中检索数据

<?php 
if(isset($_POST['userid'])){
    $editId = (int)$_POST['userid'];
    $query = "SELECT * FROM contact WHERE userid = $editId";
    $runQuery = mysqli_query($connect, $query);
    if(!$runQuery){
        die("Could not run query ".mysqli_error($connect));
    }
    $getData = mysqli_fetch_assoc($runQuery);
    echo json_encode($getData);

}

This is my js file 这是我的js文件

$(document).ready(function(){

$("#insertData").submit(function(event){
    event.preventDefault();
    if($("#name").val() == ""){
        $("#nameError").css("display", "block").html("Name is required");
    }else if ($("#email").val() == "") {
        $("#emailError").css("display", "block").html("Email is required");
    }else if ($("#description").val() == "") {
        $("#descriptionError").css("display", "block").html("Description is required");
    }else{
        $.ajax({
            url: "index.php",
            method: "POST",
            data: $("#insertData").serialize(),
            success: function(data){
                $("#success").css("display", "block").html("Data added");
                $("#insertData")[0].reset();
            }
        });
    }

});

$(document).on("click", ".edit-data", function(){
    var contactId = $(this).attr("id");
    $.ajax({
        url:"index.php",
        method: "POST",
        data: {contactId:contactId},
        dataType: "json",
        success: function(data){
            $("#name").val(data.name);
            $("#email").val(data.email);
            $("#description").val(data.description);
            $("#contactUserId").val(data.userid);
            $("#add").val("Update");
            $("#myModal").modal("show");

        }

    });

});

$(document).on('click', '.view-data', function(){  
          var contactId = $(this).attr("id");  
          if(contactId != '')  
          {  
               $.ajax({  
                    url:"index.php",  
                    method:"POST",  
                    data:{contactId:contactId},  
                    success:function(data){  
                         $('#contactDetail').html(data);  
                         $('#viewModal').modal('show');  
                    }  
               });  
          }            
     });

}); }）;

Answer 1

You are sending contactId and in your PHP you are looking for userid . 您正在发送contactId并且在您的PHP中，您正在寻找userid 。 Change your data to data: { userid: userid } . 将您的数据更改为data: { userid: userid } 。

$(document).on("click", ".edit-data", function() {

    var userid = $(this).attr("id");

    $.ajax({
      url: "index.php",
      method: "POST",
      data: { userid: userid },
      dataType: "json",
      success: function(data) {
        $("#name").val(data.name);
        $("#email").val(data.email);
        $("#description").val(data.description);
        $("#contactUserId").val(data.userid);
        $("#add").val("Update");
        $("#myModal").modal("show");
      }
    });
});

我试图使用ajax从数据库中检索数据并填充在引导模式中的表单

问题描述

1 个解决方案

解决方案1
0 2019-04-24 08:03:32

我试图使用ajax从数据库中检索数据并填充在引导模式中的表单

问题描述

1 个解决方案

解决方案1 0 2019-04-24 08:03:32

解决方案1
0 2019-04-24 08:03:32