ANSI C YACC语法中的歧义

Question

I'm watching ANSI C YACC grammar. And there is something that I don't understand. http://www.lysator.liu.se/c/ANSI-C-grammar-y.html#expression

assignment_expression
    : conditional_expression
    | unary_expression assignment_operator assignment_expression
    ;

constant_expression
    : conditional_expression
    ;

Here are the rules for assignment expression and constant expression. My question is that how can they both use conditional_expression to reduce? If there is a token reduced to a conditional_expression, after the token reduced how does YACC parser know how to reduce the token next between assignment_expression and constant_expression ? I think I'm missing something huge but I can't find that by myself. Thank you

Answer 1

There is no ambiguity because there is no context in which both assignment_expression and constant_expression may appear.

There is absolutely nothing wrong with having rules of the form

a: z;
b: z;
c: z;

if a , b , and c all appear in different contexts. If you have the following

t: a | b | c;

then there's a problem. But there's nothing like that for conditional_expression .

Answer 2

A EBNF grammar can have multiple valid rules/states at the same time.That means in this case if it finds a conditional it can match an assignment_expression and a constant_expression at the same time. To get an unique answer the rules using these two rules must be specific enough to match a given input sequence only to a single sequence of rules or you can use priorities to select a single sequence of rules from multiple possible sequences.