正则表达式只匹配字母，空格和非英语字符？

Question

I am trying to check text with regular expression and i need to check if it contains only letters, spaces and also non english characters.

I have this one:

var check = /^[a-zA-Z_0-9][a-zA-Z_0-9\s]*$/g.test(input.value);

It works fine but if input.value contains "ã" or "é" it gives false.

I googled and find that you can use unicode filter like this:

/\p{L}/u

I tryed to combine but with no results.

How can i solve this?

Thank you all.

Answer 1

The following will include extended latin characters:

var check = /^[a-zA-Z_0-9\u00C0-\u017F][a-zA-Z_0-9\u00C0-\u017F\s]*$/g.test(input.value);

See https://en.wikipedia.org/wiki/Latin_script_in_Unicode for more information.