使用grep regex选择第一个连字符

Question

echo "Linux/DEB/mainbinary-0.1.20190424165331-0-armdef.deb" | grep -oE "([^\/]+$)"

This prints just the filename, without the directory structure, but I cannot manage to print just mainbinary from that string. Suggestions?

Answer 1

echo "Linux/DEB/mainbinary-0.1.20190424165331-0-armdef.deb"  |grep -oP '.*/\K[^-]+'
mainbinary

This will scan till last / and ignore everything to its left and keep moving until - (excluding)

Answer 2

And a sed alternative to PS.'s great grep -oP

echo "Linux/DEB/mainbinary-0.1.20190424165331-0-armdef.deb"  |sed -r 's#^.*/([^-]+).*#\1#'
mainbinary

Answer 3

With any awk in any shell on any UNIX machine:

$ echo "Linux/DEB/mainbinary-0.1.20190424165331-0-armdef.deb" | awk -F'[/-]' '{print $3}'
mainbinary