如何根据列表值对元组进行排序？

Question

I have a with this structure:

players={ 'Player one': [3, 0], 'Player two': [13, 1], 'Player three': [29, 0], 'Player four': [19, 5] }

The first number of the list is the number of games and the next is the number of goals.

To sort the array by the number of games I just use:

print sorted(players.items(), key=lambda kv:(kv[1], kv[0]),reverse=True)

This works great but I found no way to sort by the number of goals (the second number of the list). What is the easiest way to do this?

Answer 1

You could sort exclusively by the second number of the list with this:

sorted(players.items(), key=lambda kv: kv[1][1], reverse=True)

Where lambda kv: kv[1][1] basically extracts the second [1] value of each list kv[1]

Answer 2

You can simply specify searching through the second index:

players={ 'Player one': [3, 0], 'Player two': [13, 1], 'Player three': [29, 0], 'Player four': [19, 5] }

sorted(players.items(), key=lambda kv:(kv[1][1], kv[0]),reverse=True))