我如何修复此代码以使其修剪尾随零和小数点

Question

I need to trim the trailing 0s and decimal point, I tried the following code and it wouldn't work. I'm using PostgreSQL and the end result would look something like (from displaying 1234.00 to "1234 ft")

SELECT TRIM(TRAILING "0" FROM ROUND("Length"::numeric * 3.28084, 2)) || ''ft'' AS "Length"

Error code I'm getting:

ERROR:  column "Length" does not exist
LINE 1: SELECT TRIM(TRAILING '0' FROM ROUND("Length"::numeric * 3.28...
                                            ^                       ^

Answer 1

Try this:

select concat(substring(cast(cast(1234.00 as decimal(10,2)) as varchar(50)),1,
position('.' in cast(cast(1234.00 as decimal(10,2)) as varchar(50)))-1),' ft')
as Length

Test Result:

DB<>Fiddle

Update:

I just found an easier one

select concat(cast(1234.00 as decimal(10,0)),' ft') as Length
from ...

Replace 1234.00 with your column name and add 'from' clause.

Answer 2

I would just do:

SELECT ("Length"::numeric * 3.28084)::int || 'ft' as Length

You can round() as well. The point is to convert to an integer so you have no decimals.