[英]Comparing N bytes in string
I want to compare argv[1] and the string "pid", but I want to put restrict how much bytes to be compared. 我想比较argv [1]和字符串“ pid”,但是我想限制要比较的字节数。 I used strncmp, but there are problem, if I put on third argument 3 it compares more than 3 bytes. 我使用了strncmp,但是有问题,如果我输入第三个参数3,它将比较3个字节以上。
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[]){
if (argc < 2)
exit(EXIT_FAILURE);
size_t i = 3;
if (strncmp(argv[1], "pid", i) == 0){
printf("%ld\n", (long)getpid());
}
}
in the terminal 在终端
$./main pid
343
$ ./main pidd
354
$ ./main piddd
352
strncmp()
compares three bytes in all of your three calls. strncmp()
比较所有三个调用中的三个字节。 But because it only compares 3 bytes, you can't tell whether the argv[0]
string ends after 3 characters or not. 但是因为它只比较3个字节,所以您无法确定argv[0]
字符串是否以3个字符结尾。
If you want "pid"
not to maych piddddd
, try comparing 4 bytes, so that you hit the end-of-string marker ( '\\0'
). 如果您想让"pid"
不增加piddddd
,请尝试比较4个字节,以便您击中字符串结尾标记( '\\0'
)。
This might work: 这可能起作用:
int i,count=1;
char str[] = "pid";
for (i = 0;i < 4;i++)
{
if (str[i] != argv[1][i])
{
count = 0;
break;
}
}
if(count==1)
printf("%ld\n", (long)getpid());
You can have a check like this below: 您可以在下面进行如下检查:
if ((strlen(argv[1]) <= i) && strncmp(argv[1], "pid", i) == 0){
But for all three possible inputs you tried, the first 3bytes are "pid". 但是对于您尝试过的所有三个可能的输入,前3个字节均为“ pid”。 So strncmp will obviously returns 0 and is expected only. 因此,strncmp显然将返回0并且仅是预期值。
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