char **是指向C中字符串数组的指针吗？

Question

From my understanding, char* X is a variable that points to a single character or a character array (string) in C.

char** is a pointer which points to another pointer which finally points to a single character or a character array.

if int** is equivalent to creating a multidimensional array, why can't I create an array of strings in C using char** ?

const char** day = {
    "Sunday",
    "Monday",
    "Tuesday",
    "Wednesday",
    "Thursday",
    "Friday",
    "Saturday"
};

Here *day would point to the array itself and **day would point to the first element of the array "Sunday"?

Answer 1

why can't I create an array of strings in C using char**? yes you can create. Correct way is to use array of char pointers not the double char** pointer as you did. For eg

const char* day[7] = {
    "Sunday",
    "Monday",
    "Tuesday",
    "Wednesday",
    "Thursday",
    "Friday",
    "Saturday"
};

Above, day is array of char pointers and its each element is character pointer and each elements needs to point to valid address. Here day[0] is character pointer & its pointing to string literal sunday which is valid address.

Its also possible via char** but not the way as you did. For eg

char **day = {"sunday", "Monday" };

here problem is you haven't allocated memory for day[0] , day[1] to hold some string literal like sunday & so on.

First allocate memory for day like below

char **day = malloc(NUM_OF_DAYS * sizeof(*day)); /* define NUM_OF_DAYS as 7 */

And then allocate memory for day[0] , day[1] etc.

for(int index =0 ; index < NUM_OF_DAYS; index++) {
   day[index] = malloc(MAX_DAY_SIZE * sizeof(**day)); /* define this MACRO */
}

And then you scan the data at run time.

Answer 2

char* X is a variable that points to a single character or a character array (string) in C.

No, it is a variable that contains the address of a single character. That single character may or may not be the beginning of a null terminated string.

Thus char** points at a char* that points at a character.

if int** is equivalent to creating a multidimensional array

It is not. int** has nothing to do with multi-dimensional arrays.

why can't I create an array of strings in C using char** ?

Because a char** is not an array nor can it, strictly speaking, point at one.

---

A char* can be used to point at a null terminated string. So if you want an array of strings, you need an array of char* . Which can for example be written as:

char* day[] = { ... };

Now as it turns out, a char** can be used to point at the address of the first item of this array, &day[0] , since that is a char* . This often make people confuse char** for multi-dimensional arrays, because it is valid to do this:

char* day[] = { "Sunday", ... };
char** week = &day[0];
printf("%c", week[0][0]); // prints 'S'

But that does not make char** an array, nor does it make it a 2D array.

You can also use char** to dynamically allocate a look-up table of strings, where each string has a variable length:

char** week = malloc(7 * sizeof(char*));
for(int i=0; i<7; i++)
{
  week[i] = malloc( ... );
}

Here again, the char** points at the first item of a 1D array of char* . It is not a 2D array, it does not point at one. That it allows week[i][j] syntax is irrelevant, it is still not an array (and [] is never actually used on array types, Do pointers support “array style indexing”? ).

More info: Correctly allocating multi-dimensional arrays .