Oracle SQL：根据多个行条件拆分组

Question

I have data where a single address can have multiple journeys, something like this:

I want to split the address by each journey ("Start of Journey" to "End of Journey" and all "Part of Journeys" in the middle constitute one Journey) and aggregate the costs, so each address can have multiple rows based on the number of journeys, something like this:

I just can't seem to figure out the logic that I would need to use to solve this. Any help or pointers would be highly appreciated.

Answer 1

Use a running sum to tag rows into groups, starting a new number whenever Start of Journey row is encountered for a given address. Then use it to group and get the total cost.

select address,sum(cost) 
from (select t.*
      --Replace OrderCol with a column that specifies row order
      ,sum(case when journey='Start of Journey' then 1 else 0 end) over(partition by address order by OrderCol) as grp 
      from tbl
     ) t
group by address,grp