如何遍历单词列表并用单词替换某些字母

Question

I am trying to iterate through a list of several words. If a certain letter is present it will replace that letter and add a word to the existing word. But it will only work on words in the list that have that letter.

list1 = ['06h', '12d', '05h', '04s', '12s', '12c']
#list2 = list(x+'sample' for x in cards)

or 

for x in cards:
    if 's' in x:
        cards.append('ample')[0]

This will add 'sample' to everything, i dont know how to make it only add 'sample' to cells with the letter "s".

list1 = [06h', '12d', '05h', '04s', '12s', '12c']
if "s" in list1:

Should show

list2 = [06h', '12d', '05h', '04sample', '12sample', '12c']

Answer 1

Use a comprehension checking if the strings ends in s :

>>> list1 = ['06h', '12d', '05h', '04s', '12s', '12c']
>>> [x + 'ample' if x.endswith('s') else x for x in list1]
['06h', '12d', '05h', '04sample', '12sample', '12c']

Answer 2

you can use find and can replace with samples

list1 = ['06h', '12d', '05h', '04s', '12s', '12c']
l2=[]
for item in list1:
    if item.find('s'):
        l2.append(item.replace('s','samples'))
    else:
        l2.append(item)
print(l2)

['06h', '12d', '05h', '04samples', '12samples', '12c']    

Answer 3

   list2 =[]
   for x in list1:
         if 's' in x:
            x = x.replace('s', 'sample')
         list2.add(x)

Answer 4

map(lambda x: x.replace('s','sample'), list1)

would work as well. map applies a function to every element of a list and returns a list of the results.

Python is full of tools for working with lists.