Bash：从一个目录中的脚本中打开多个具有不同名称的文件

Question

I'm trying to make screen caps/previews of multiple video files (different names). Im using script called SlickSlice, easy to use with one file.

I have tried

./slickslice-0.9 -x /dir/*

It didn't worked at all. Only first file was loaded and edited.

Script ussage with one file:

./slickslice-0.9 -x /dir/FILENAME 

How to handle multiple files in the script and add them as parameter? I saw few examples with "for" loop but it was only to rename files.

Answer 1

This might work:

for foo in /dir/*; do
  ./slickslice-0.9 -x "$foo"
done