[英]Convert Rest API JSON Response into C# object
I have a code REST API response which is json, and parsing to JObject and pulling a value from it. 我有一个代码REST API响应,它是json,并解析为JObject并从中提取一个值。 But i am getting the error when parsing to JObject.
但是我在解析到JObject时遇到错误。
Error: "Unexpected character encountered while parsing value: S. Path '', line 0, position 0." 错误:“解析值:S.Path时遇到意外字符,行0,位置0。”
Is there any other way to convert Json string to C# object. 还有其他方法可以将Json字符串转换为C#对象。
I have the following code: using Newtonsoft.Json; 我有以下代码:使用Newtonsoft.Json;
using (HttpResponseMessage message = httpclient.GetAsync(folderIdURL).Result)
{
if(message.IsSuccessStatusCode)
{
var dataobjects = message.Content.ReadAsStringAsync();
//dataobjects = "{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/","title":"DQL query results","author":[{"name":"EMC Documentum"}],"updated":"2019-05-02T15:19:52.508+00:00","page":1,"items-per-page":100,"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)"}],"entries":[{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)&index=0","title":"0b0111738011c114","updated":"2019-05-02T15:19:52.508+00:00","published":"2019-05-02T15:19:52.508+00:00","links":[{"rel":"edit","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c114"}],"content":{"json-root":"query-result","definition":"https://gbc-dev5.cloud.wc.com/DctmRest/repositori es/dmgbsap_crt/types/dm_sysobject","properties":{"r_object_id":"0b0111738011c114","object_name":"04"},"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c114"}]}},{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)&index=1","title":"0b0111738011c115","updated":"2019-05-02T15:19:52.509+00:00","published":"2019-05-02T15:19:52.509+00:00","links":[{"rel":"edit","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c115"}],"content":{"json-root":"query-result","definition":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/types/dm_sysobject","properties":{"r_object_id":"0b0111738011c115","object_name":"05"},"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c115"}]}}]}"
JObject responseObj = JObject.Parse(dataobjects.ToString());
String id = (String)responseObj["entries" -->"content"-->"properties"-->"object_name"];
}
}
} }
I am expecting the value from (String)responseObject["enteries"]["content"][" properties"]["object_name"] 我期望来自(String)responseObject [“ enteries”] [“ content”] [“ properties”] [“ object_name”]的值
JObjects are a pain. JObjects很痛苦。 You could get a sample of the JSON response and paste it into a converter like json2csharp.com.
您可以获取JSON响应的样本并将其粘贴到json2csharp.com之类的转换器中。 It will generate a class for you which you can then use like so:
它将为您生成一个类,您可以像这样使用它:
Generated Class: 生成的类:
public class MyClass
{
public string SomeProperty { get; set; }
public string AnotherProperty { get; set; }
}
Usage: 用法:
if (message.IsSuccessStatusCode)
{
var deserializedObject = JsonConvert.DeserializeObject<MyClass>(response.Content.ReadAsStringAsync().Result);
Console.WriteLine(deserializedObject.SomeProperty);
}
I would suggest to follow those steps: 我建议遵循以下步骤:
json
is actually a json
, because an error says it is not. json
实际上是json
,因为错误表明不是。 You can use online tools like this so you will have something like: 因此您将获得类似以下内容的信息:
using System;
using Newtonsoft.Json;
namespace ConsoleApp11
{
class Program
{
public class Message
{
public Enteries enteries { get; set; }
}
public class Enteries
{
public Content content { get; set; }
}
public class Content
{
public Properties properties { get; set; }
}
public class Properties
{
public string object_name { get; set; }
}
static void Main(string[] args)
{
var input = "{\"enteries\":{\"content\":{ \"properties\":{ \"object_name\":\"your value string\"}}}}";
Message msg = JsonConvert.DeserializeObject<Message>(input);
Console.WriteLine(msg?.enteries?.content?.properties?.object_name ?? "no value");
Console.ReadKey();
}
}
}
I hope it helps 😊 希望对您有帮助
Using Newtonsoft.Json 使用Newtonsoft.Json
First get the list of entries from the responseObj
. 首先从
responseObj
获取条目列表。 Then loop each entries and use LINQ to JSON to get values by property name or index. 然后循环每个条目,并使用LINQ to JSON通过属性名称或索引获取值。
You can use Item[Object]
index on JObject/JArray and then cast the returned JValue to the type you want 您可以在JObject / JArray上使用
Item[Object]
索引,然后将返回的JValue强制转换为所需的类型
JObject responseObj = JObject.Parse(dataobjects.ToString());
// get JSON result objects into a list
IList<JToken> entries = responseObj ["entries"].Children().ToList();
foreach(JToken entry in entries)
{
string object_name = (string) entry["content"]["properties"]["object_name"];
}
Thank you so much for all the help and trips. 非常感谢您提供的所有帮助和旅行。 Finally i am able to get the required value from JSON string.
最后,我能够从JSON字符串中获取所需的值。
Here is the Final code json2csharp.com 这是最终代码json2csharp.com
public class Author
{
public string name { get; set; }
}
public class Link
{
public string rel { get; set; }
public string href { get; set; }
}
public class Link2
{
public string rel { get; set; }
public string href { get; set; }
}
public class Properties
{
public string r_object_id { get; set; }
public string object_name { get; set; }
}
public class Link3
{
public string rel { get; set; }
public string href { get; set; }
}
public class Content
{
public string json_root { get; set; }
public string definition { get; set; }
public Properties properties { get; set; }
public List<Link3> links { get; set; }
}
public class Entry
{
public string id { get; set; }
public string title { get; set; }
public DateTime updated { get; set; }
public DateTime published { get; set; }
public List<Link2> links { get; set; }
public Content content { get; set; }
}
public class RootObject
{
public string id { get; set; }
public string title { get; set; }
public List<Author> author { get; set; }
public DateTime updated { get; set; }
public int page { get; set; }
public int items_per_page { get; set; }
public List<Link> links { get; set; }
public List<Entry> entries { get; set; }
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.