如何在JavaScript中按属性删除对象

Question

I would like to know how to remove the object by property in nested array object

I have whole list of object in sampleobj , compare each id with apitrans, apifund , if success is false, remove obj in sampleobj

Remove the object if the success is false, in sampleobj.

I have tried:

var result = sampleobj.foreach(e=>{
   if(e.id === "trans" && apitrans.success== true){
      Object.assign(e, apitrans);
   }
  if(e.id === "fund" && apifund.success== true){
      Object.assign(e, apifund);
   }

  // if success false remove the object.
})

//inputs scenario 1
var sampleobj=[{
    id: "trans",
    amount: "100",
    fee: 2
   },
   {
    id: "fund",
    amount: "200",
    fee: 2
   }]
var apitrans = 
  {
   success: true,
   id: "trans",
   tamount: "2000",
   fee: "12"
  }
var apifund =
  {
   success: false,
   id: "fund",
   tamount: "4000",
   fee: "10"
  } 

//inputs scenario 2 how to do same if property name differs
if error, status error, or success false remove obj in sampleobj

var sampleobj=[{
    id: "trans",
    amount: "100",
    fee: 2
   },
   {
    id: "fund",
    amount: "200",
    fee: 2
   },
{ id: "insta", amount: "400", fee: 2 }
]

var apitrans = {success: true,id: "trans",tamount: "2000",fee: "12"}
var apiinsta = { errors: [{code:"error.route.not.supported"}],id: "insta",tamount: "2000",fee: "12"}
var apifund = { status: "error", id: "fund", tamount: "4000", fee: "10" }

var sampleobj=[{
//Expected Output
result: [
  {
    id: "trans",
    amount: "100",
    fee: 2
  }
]```

Answer 1

You can use filter() to remove elements from array.

• Create a helper function( func ) which takes two objects as parameter and compare id property of both and check success property of one of them.
• Then use filter() of the given array and put both given objects array [apitrans,apifund] .
• Then use some() method on [apitrans,apifund] and check if any of them have id equal the current element using Helper Function.

 var arr=[ { id: "trans", amount: "100", fee: 2 }, { id: "fund", amount: "200", fee: 2 } ] var apitrans = {success: true,id: "trans",tamount: "2000",fee: "12"} var apifund = { success: false, id: "fund", tamount: "4000", fee: "10" } const func = (obj1,obj2) => obj1.id === obj2.id && obj2.success const res = arr.filter(x => [apitrans,apifund].some(a => func(x,a))); console.log(res) 

Answer 2

You can filter out your array with conditions ie filter gives you new array instead of changing the original array

 var arr = [{ id: "trans", amount: "100", fee: 2 }, { id: "fund", amount: "200", fee: 2 } ] var apitrans = { success: true, id: "trans", tamount: "2000", fee: "12" } var apifund = { success: false, id: "fund", tamount: "4000", fee: "10" } var filter = arr.filter(function(item) { //console.log(item); if (item.id === apitrans.id && apitrans.success) { return item } }); console.log(filter); 

Or if you want an original array to be modified instead of getting a new array, you can use your given approach with some update ie

 var arr = [{ id: "trans", amount: "100", fee: 2 }, { id: "fund", amount: "200", fee: 2 } ] var apitrans = { success: true, id: "trans", tamount: "2000", fee: "12" } var apifund = { success: false, id: "fund", tamount: "4000", fee: "10" } arr.forEach(e => { if (e.id === "trans" && apitrans.success == true) { Object.assign(e, apitrans); } else if (e.id === "fund" && apifund.success == true) { Object.assign(e, apifund); } else { // if success false remove the object. var index = arr.indexOf(e); arr.splice(index, 1); } }) console.log("resulted original arr", arr)