正则表达式从短语开始到带条件的文档结尾

Question

I have a starting phrase say fruits . I have some ending phrase like apple , banana and pineapple .

I have some documents with variable as text :

1. Fruits

   They are good for health....

   should eat Apple

2. Fruits

   eat regularly banana

   Fruits you need

   to eat Apple

3. Fruits are good

   Daily we should have pineapple

   In general, fruits have various minerals.

   Most of them are very tasty

My Regex and code:

p = r'(\bFruits\b\s*\w*\s*\n*.*?(\bApples?\b|\bbananas?\b|\bpineapples?\b))'
sep = ";;"
lst = re.findall(p, text, re.I|re.M|re.DOTALL)
val = sep.join(str(v) for v in lst )

Above regex works well in text 1 & 2 and partially in text 3.

Problem :

All I need is when we encounter fruit and don't find any of the ending phrase, then and only then go till end of document.

Expected Output from text 3 :

Fruits are good Daily we should have pineapple ;; fruits have various minerals.
Most of them are very tasty

PS : I tried $ as well, but that was also not working.

Answer 1

include \\Z in the expression as follows

text = '''Fruits are good

Daily we should have pineapple

In general, Fruits have various minerals.

Most of them are very tasty
'''

p = r'(\bFruits\b\s*\w*\s*\n*.*?(\bApples?\b|\bbananas?\b|\bpineapples?\b|\Z))'
sep = ";;"
lst = re.findall(p, text, re.I|re.M|re.DOTALL)
val = sep.join(str(v) for v in lst )
print(val)

output is as follows

('Fruits are good\\n\\nDaily we should have pineapple', 'pineapple');;('Fruits have various minerals.\\n\\nMost of them are very tasty\\n', '') [Finished in 0.1s]