解决方法：排序方法

Question

Here is my method that handles sorting an array of strings

func bucketNameGenerator(player1Id: String, player2Id: String) -> String { 
    var bucketName : String =  ""
    var uniqueBucketID = [String]()

    uniqueBucketID = [player1Id, player2Id]

    let sortedUniqueBucketID = uniqueBucketID.sorted(by: <)

    bucketName = sortedUniqueBucketID.joined().replacingOccurrences(of: "$", with: "")

    print("[bucketNameGenerator] bucketName: \(bucketName)")

    return String(bucketName)
}

The two string values aren't pure strings they contain number values as well. this way of sorting does not return the same value each time. Need suggestions on improvement here / directed down a path to create an asymmetric string each time.

Example Expected Results:

player1Id : 123jinrk1412941jdlndma
player2Id: 49812u4jldanec192hce12n

expected result both combined and sorted in an ascending order :
49812u4jldanec192hce12n123jinrk1412941jdlndma

The above example isn't correctly sorted but the goal is to get a string that is the same every-time the method runs with two inputted values.

Answer 1

Calling sorted for just two items is overkill.

To consider numeric values compare the strings with option numeric

func bucketNameGenerator(player1Id: String, player2Id: String) -> String {
    let result : String
    if player1Id.compare(player2Id, options: .numeric) == .orderedAscending {
        result = player1Id + player2Id
    } else {
        result = player2Id + player1Id
    }
    return result.replacingOccurrences(of: "$", with: "")
}

Answer 2

Maybe you intended to use > ?

func bucketNameGenerator(player1Id: String, player2Id: String) -> String {
    let uniqueBucketID = [player1Id, player2Id]

    let sortedUniqueBucketID = uniqueBucketID.sorted(by: >)

    let bucketName = sortedUniqueBucketID.joined().replacingOccurrences(of: "$", with: "")

    return bucketName
}

Or simpler :

func bucketNameGenerator(player1Id: String, player2Id: String) -> String {

    let output = player1Id < player2Id ?
    player2Id + player1Id : player1Id + player2Id

    return output.replacingOccurrences(of: "$", with: "")
}