[英]Control structures (IF/ELSE)
I try to create plsql block but it doesnt work. 我尝试创建plsql块,但是它不起作用。 Oracle says that i have error at line 2. I think it could be because substitution variable is not placed right !?
甲骨文说我在第2行有错误。我认为可能是因为替换变量放置不正确!
DECLARE
V_ENAME EMPLOYEES.LAST_NAME%TYPE := '&LNAME';
V_SAL EMPLOYEES.SALARY%TYPE;
BEGIN
SELECT LAST_NAME, SALARY
INTO V_ENAME, V_SAL
FROM employees WHERE LAST_NAME = V_ENAME;
IF V_SAL < 3000 THEN
v_sal := v_sal + 500;
DBMS_OUTPUT.PUT_LINE (v_ename || 'have increasement ');
ELSIF V_SAL > 3000 THEN
DBMS_OUTPUT.PUT_LINE (v_ename || 'do not have increasement ');
ELSE
DBMS_OUTPUT.PUT_LINE ('error');
END IF;
END;
Since there can be many employees with the last name passed by the user, you may use an implicit CURSOR FOR LOOP
. 由于可能有很多员工使用用户传递的姓氏,因此可以使用隐式
CURSOR FOR LOOP
。 Also, add first_name
in the output for clarity. 另外,为清楚起见,在输出中添加
first_name
。
DECLARE
v_ename employees.last_name%TYPE := '&LNAME';
v_sal employees.salary%TYPE;
BEGIN
for rec IN ( SELECT first_name,last_name,salary
FROM employees WHERE last_name = v_ename
)
LOOP
IF rec.salary < 3000 THEN
v_sal := rec.salary + 500;
dbms_output.put_line (rec.first_name||' '||rec.last_name ||
' has an increase');
ELSIF rec.salary > 3000 THEN
dbms_output.put_line (rec.first_name||' '||rec.last_name ||
' does not have an increase ');
ELSE dbms_output.put_line ('error');
END IF;
END LOOP;
END;
/
Execution 执行
..
old:DECLARE
v_ename employees.last_name%TYPE := '&LNAME';
..
new:DECLARE
v_ename employees.last_name%TYPE := 'Grant';
..
Douglas Grant has an increase
Kimberely Grant does not have an increase
PL/SQL procedure successfully completed.
不知道这是否是您的问题,但是当您已经确保where子句中的last_name等于v_ename时,实际上无需在v_ename中选择last_name。
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