如何使用Tensorflow查找值的立方根？

Question

I have tried the following:

>>> import tensorflow as tf
>>> tf.enable_eager_execution()
>>> tf.math.pow(3,3)
2019-05-06 16:05:51.508296: I tensorflow/core/platform/cpu_feature_guard.cc:141] Your CPU supports instructions that this TensorFlow binary was not compiled to use: AVX2
<tf.Tensor: id=3, shape=(), dtype=int32, numpy=27>
>>> tf.math.pow(9,(1/3))
<tf.Tensor: id=7, shape=(), dtype=int32, numpy=1>
>>> tf.math.pow(27,(1/3))
<tf.Tensor: id=11, shape=(), dtype=int32, numpy=1>
>>> tf.math.pow(27,0.3)
<tf.Tensor: id=15, shape=(), dtype=int32, numpy=1>
>>> tf.math.pow(4,0.5)
<tf.Tensor: id=19, shape=(), dtype=int32, numpy=1>
>>> tf.math.pow(4,1/2)
<tf.Tensor: id=23, shape=(), dtype=int32, numpy=1>

I know that sqrt is used for square root. But if I need the cube root of a number, how I can calculate it with tensorflow?

Answer 1

Try this please:

>>> import tensorflow as tf
>>> tf.enable_eager_execution()
>>> tf.math.pow(27.0,1.0/3.0)
2019-05-06 16:22:39.403646: I tensorflow/core/platform/cpu_feature_guard.cc:141] Your CPU supports instructions that this TensorFlow binary was not compiled to use: AVX2
<tf.Tensor: id=3, shape=(), dtype=float32, numpy=3.0>

Guess the issue is with datatype.

Answer 2

If you mean seeing the result, you can use InteractiveSession and eval :

import tensorflow as tf
tf.InteractiveSession()
tf.pow(27.0,1/3).eval()