将字典键和值插入python列表

Question

I was trying to insert key and value of my dictionary to a python list.I cant seem to figure it out how to do this.

my_dict={test1:[1,2,3,4],test2:[2,3,4,5]}

what I want is

my_list = [['test1', 1,2,3,4], ['test2', 2,3,4,5]]

I am new to python so any help would be appreciated.

Answer 1

This should do it
We need to iterate over the dictionary, and make a list with the key and values, note that we need to unroll the value array *value in order to append to the list

my_dict={'test1':[1,2,3,4],'test2':[2,3,4,5]}

#Iterate over key and value, and make a list from them, unrolling the value since it is a list
my_list = [[key, *value] for key, value in my_dict.items()]
print(my_list)
#[['test1', 1, 2, 3, 4], ['test2', 2, 3, 4, 5]]

Answer 2

Using a list comprehension

Ex:

my_dict={"test1":[1,2,3,4],"test2":[2,3,4,5]}

my_list = [[k] +v for k, v in my_dict.items()]
print(my_list)

Output:

[['test1', 1, 2, 3, 4], ['test2', 2, 3, 4, 5]]

Answer 3

The other solutions use list comprehensions which may be too complicated for someone who is new to python, so this is a solution without list comprehension.

my_dict={"test1":[1,2,3,4],"test2":[2,3,4,5]}

new_list = []
for key, value in my_dict.items():
    print(key, value)

    temp = []
    temp.append(str(key))
    for a in value:
        temp.append(a)
    new_list.append(temp)

print(new_list) 
# [['test1', 1, 2, 3, 4], ['test2', 2, 3, 4, 5]]

Answer 4

Here's a version without the list comprehension, I remember it took me a couple months to understand the syntax when I was new to python.

my_dict={'test1':[1,2,3,4],'test2':[2,3,4,5]}

my_list = []

for key, value in my_dict.items():
    my_list.append([key, *value]) # the '*value' bit means all elements of the 'value' variable

print(my_list)

Answer 5

FOMO:

my_dict={'test1':[1,2,3,4],'test2':[2,3,4,5]}
x = lambda a:[a[0],*a[1]]; print([x(i) for i in my_dict.items()])
#[['test1', 1, 2, 3, 4], ['test2', 2, 3, 4, 5]]