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Tableau检查两组中的多个ID

[英]Tableau check for multiple IDs across 2 groups

I want to create a set in tableau, which will show either one of these two values: Y or N 我想在tableau中创建一个集合,它将显示以下两个值中的一个:Y或N.

2 already existing columns are here important, "VAT-ID" and "CUSTOMER-ID". 2现有的列在这里很重要,“VAT-ID”和“CUSTOMER-ID”。 the new column should check if a customer-ID has multiple VAT-IDs. 新列应检查客户ID是否包含多个VAT-ID。 If yes, the value "Y" should be displayed, else "N". 如果是,则应显示值“Y”,否则显示“N”。 The table looks like: 该表看起来像:

customer-id  VAT-id       in-both
123456       EE999999999  Y
654321       AA999999999  N
666666       GG999999999  N 
123456       KK999999999  Y
654321       AA999999999  N

any Help would be appreciated, I have tried IF [CustomerID] = 1 AND Count([VAT-ID]) > 1 THEN 'Y' ELSE 'N' END which didn't work. 任何帮助将不胜感激,我已经尝试过IF [CustomerID] = 1 AND Count([VAT-ID]) > 1 THEN 'Y' ELSE 'N' END无法正常工作。

You are close. 你很亲密 For this you need an LOD (Level of Detail) expression. 为此,您需要一个LOD(细节级别)表达式。 LOD expressions allow you to do calculations at a different granularity then the view is rendered. LOD表达式允许您以不同的粒度进行计算,然后呈现视图。

You can use: 您可以使用:

if 
{fixed [Customer-Id]: countd([VAT-id]) } > 1
then 'Y'
else 'N'
end

The LOD is the {fixed...} . LOD是{fixed...} The way you read this is you want to count the distinct number of VAT-id per each Customer-id. 您阅读本文的方式是,您希望计算每个Customer-id的VAT-id的不同数量。 (eg 123456 will return 2; all others will return 1). (例如123456将返回2;所有其他人将返回1)。 Then you just wrap that in an If statement. 然后你只需将它包装在If语句中。

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