如果不起作用，请让函数进入内部。 （没有错误信息）

Question

Im making a snake game. I got the problem that if the snake gets into the same position as the food the food respawns to a different place.

Nophing, I can't find the error anywhere in internet.

function draw (){

    if(snakeX == food.x && snakeY == food.y){
        score++;
        eat.play();
        let food = {
            x : Math.floor(Math.random()*17+1) * box,
            y : Math.floor(Math.random()*15+3) * box
        }

It is supposed to add a point to the score, make a sound, replace the food.

Now it is adding a point and making a sound.

Answer 1

You need to remove the let statement , because you create a new local variable with a scope only in the block. Outside the variable keeps the same value without changing to the new value.

if (snakeX == food.x && snakeY == food.y) {
    score++;
    eat.play();
    food = {                                         // without let
        x: Math.floor(Math.random() * 17 + 1) * box,
        y: Math.floor(Math.random() * 15 + 3) * box
    };
}

Please have a look to this example:

x gets a new local scope with an own value. The outer variable x stays.

 let x = { a: 42 }; if (true) { let x = { b: 0 }; console.log(x); // b ... } console.log(x); // a ...