从词典列表中创建一个新词典

Question

I have a list of dictionaries :

dicti = [{**'product':** 'Cereal', 'price': 12.99},
     {**'product'**: 'Cereal1', 'price': 9.99}, 
     {**'product'**: 'Cereal2', 'price': 11.99},
     {**'product'**: 'Cereal', 'price' : 15.83}, 
     {**'product'**: 'Cereal1', 'price': 10.99}, 
     {**'product'**: 'Cereal2', 'price': 9.99}]

My goal is to find the product with the top total of sales :

Output = [Cereal, 28.82]

So far, I have been able to extract dictionaries to a list:

list = [['Cereal',12.99,'Cereal1',9.99,'Cereal2', 11.99,'Cereal', 15.83, 'Cereal1, 10.99,'Cereal2',9.99] 

Is this a proper way? or What is the best way to do it?

Thanks!

Answer 1

You can use collections.Counter to accumulate the price for each product , then take the max at the end:

from collections import Counter
from operator import itemgetter

dicti = [
    {"product": "Cereal", "price": 12.99},
    {"product": "Cereal1", "price": 9.99},
    {"product": "Cereal2", "price": 11.99},
    {"product": "Cereal", "price": 15.83},
    {"product": "Cereal1", "price": 10.99},
    {"product": "Cereal2", "price": 9.99},
]

counts = Counter()
for x in dicti:
    counts[x["product"]] += x["price"]

print(max(counts.items(), key=itemgetter(1)))
# ('Cereal', 28.82)

If you want the result to be a list instead of tuple :

print(list(max(counts.items(), key=itemgetter(1))))
# ['Cereal', 28.82]

Answer 2

 import pandas as pd
 dicti = [{'product': 'Cereal', 'price': 12.99},
 {'product': 'Cereal1', 'price': 9.99}, 
 {'product': 'Cereal2', 'price': 11.99},
 {'product': 'Cereal', 'price' : 15.83}, 
 {'product': 'Cereal1', 'price': 10.99}, 
 {'product': 'Cereal2', 'price': 9.99}]

 sd = pd.DataFrame.from_dict(dicti  )

 sd.groupby('product').sum()

This will give you the sum as expect

Cereal 28.82 Cereal1 20.98 Cereal2 21.98