字符串的二进制表示

Question

Assuming I have some ASCII characters in a string, let's say s = ABC , how can I retrieve the binary representation as a string?

In this case,

A = '01000001'
B = '01000010'
C = '01000011'

so I want something like make_binary('ABC') to return '010000010100001001000011'

I know I can get the hex values for a string. I know I can get the binary representation of an integer. I don't know if there's any way to tie all these pieces together.

Answer 1

Use the ord() funcction to get the integer encoding of each character.

def make_binary(s):
    return "".join([format(ord(c), '08b') for c in s])
print(make_binary("ABC"))

08b formatting returns the number formatted as 8 bits with leading zeroes.

Answer 2

I think the other answer is wrong. Maybe I interpret wrongly the question.

In any case, I think you are asking for the 'bit' representation. Binary often is used for bytes representation (the .bin files, etc.)

The byte representation is given by an encoding, so you should encode the string, and you will get a byte array. This is your binary (as byte) representation.

But it seems you are asking 'bit-representation'. That is different (and the other answer, IMHO is wrong). You may convert the byte array into bit representation, like on the other answer. Note: you are converting bytes. The other answer will fails on any characters above 127, by showing you only the binary representation of one byte.

So:

def make_binary(s):
    return "".join(format(c, '08b') for c in s.encode('utf-8'))

and the test (which file on @Barmar answer).

>>> print(make_binary("ABC"))
010000010100001001000011
>>> print(make_binary("Á"))
1100001110000001