如何使这个jquery代码激活函数本身，而不是绑定到一个按钮来激活该函数？

Question

How to make this jquery code fire the function itself instead of binding to a button to fire the function?

self.ShowWindow= { observable: ko.observable(false) };
self.OnToggleShowWindow = (it) => () => it.observable(!it.observable());
$('#showWindowButton').click(self.OnToggleShowWindow (self.ShowWindow));

Right now I have to create a button and bind it with my code to be able to trigger a function in my react component. What I'm wondering is that, is it possible to just trigger the function without halving to trigger the jquery click?

My ViewModel in the javascript component.

$ViewModel = function (element) {
    var self = this;

    self.ShowWindow= { observable: ko.observable(false) };
    self.OnToggleShowWindow = (it) => () => it.observable(!it.observable());
    self.OnToggleShowWindow (self.ShowWindow);
    $(document).ready(function () {
        self.OnToggleShowWindow(self.ShowWindow)
    };

    self.ShowDialog = function (componentId, componentName) {
       // The fucntion OnToggleShowWindow is supposed to be called here
    };
}

Only outside the ShowDialog function is bound at rendering the page. After what the showdialog is just a function that updates on the already bounded observables.

In my react component I have subscribed to the function, which I now try to retrieve:

this.props.toggleShowWindow.observable.subscribe(this.onToggleShowWindow);

Answer 1

Put () after it instead of passing it to click .

 $('#showWindowButton').click(self.OnToggleShowWindow (self.ShowWindow)); 

becomes:

self.OnToggleShowWindow(self.ShowWindow)()

---

Don't forget the () after it. Pay close attention to the above line of code and make sure you don't miss any () out.