如何通过python套接字运行多个命令

Question

I have problem with my code, I want to run a commands on my virual machines via sockets. I found problem with multiple tasks,commands. For example if I open Excel my socket server has been freezed and I cannot run another command via cmd before I close excel application manually.

What I should change in code to open multiple applications in one time on my virtual machine? (for example. I want to open in one time four xlsx files)

Server.py

import socket
import subprocess
import os
from threading import Thread


def check_ping(hostname):
    response = os.system("ping " + hostname)
    # and then check the response...
    if response == 0:
        pingstatus = "Network Active"
    else:
        pingstatus = "Network Error"

    return(pingstatus)

def run_path(path):
    response = os.system(path)
    # and then check the response..
    return('ok')



def Main():
    host = "localhost"
    port = 5000

    mySocket = socket.socket()
    mySocket.bind((host,port))

    mySocket.listen(1)
    conn, addr = mySocket.accept()
    print ("Connection from: " + str(addr))
    while True:
            data = conn.recv(1024).decode()
            if not data:
                    break
            #print ("from connected  user: " + str(data))

            #data = str(data)
            #hostname = data.replace('ping ', '')

            print ("sending: " + str(data))
            #print(hostname)
            conn.send(data.encode())
            if 'ping' in str(data):
                hostname = data.replace('ping ', '')
                pingstatus = check_ping(hostname)
                print(pingstatus)
            elif 'open' in str(data):
                path = str(data).replace('open ', '')

                run_path(path)





    conn.close()

if __name__ == '__main__':
    Main()

Client.py

import socket

def Main():
        host = '127.0.0.1'
        port = 5000

        mySocket = socket.socket()
        mySocket.connect((host,port))

        message = input(" -> ")

        while message != 'q':
                mySocket.send(message.encode())
                data = mySocket.recv(1024).decode()

                print ('Received from server: ' + data)

                message = input(" -> ")

        mySocket.close()

if __name__ == '__main__':
    Main()

Answer 1

Te be able to run a new command before the previous one has returned, you have just not to wait for that event. That means that you should use the subprocess module instead of the system function:

def run_path(path):
    response = subprocess.Process(path, shell=True)
    # and then continue without waiting...
    return('ok')

But it does not really make sense if you want to return anything to the peer. In addition, it does not really make sense to launch a GUI program from a remote client without being able to control it, nor even to stop it.

I am afraid you a chasing a weird animal here...