[英]Remove all matching value from a list of lists
I have following list of lists object 我有以下列表对象列表
myList = [[123,0.0,345,0.0,0.0,0.0],
[45,0.0,0.0,0.0],
[67,8,0.0,5,6,7,0.0]
And I want to remove all zeroes from this list. 我想从此列表中删除所有零。
I followed this question and coded like following. 我遵循了这个问题,并按如下所示进行编码。
myList = list(filter(lambda j:j!=0,myList[i]) for i in range(len(myList)))
But I am getting the list of filter object as the output. 但是我正在获取过滤器对象列表作为输出。 What is the error in the code. 代码中有什么错误。
[<filter object at 0x7fe7bdfff8d0>, <filter object at 0x7fe7a6eaaf98>, <filter object at 0x7fe7a6f08048>,
You forgot to cast the inner filter
function with a list
, when you do that, the code works as expected :) 您忘记使用list
强制转换内部filter
功能,执行此操作时,代码将按预期工作:)
myList = [[123,0.0,345,0.0,0.0,0.0],
[45,0.0,0.0,0.0],
[67,8,0.0,5,6,7,0.0]]
#Cast inner filter into a list
myList = list(list(filter(lambda j:j!=0,myList[i])) for i in range(len(myList)))
print(myList)
The output will be 输出将是
[[123, 345], [45], [67, 8, 5, 6, 7]]
Also a simpler way of understanding will be to use a list-comprehension 同样,更简单的理解方式是使用列表理解
myList = [[123,0.0,345,0.0,0.0,0.0],
[45,0.0,0.0,0.0],
[67,8,0.0,5,6,7,0.0]]
#Using list comprehension, in the inner loop check if item is non-zero
myList = [ [item for item in li if item != 0] for li in myList ]
print(myList)
The output will be 输出将是
[[123, 345], [45], [67, 8, 5, 6, 7]]
Try this : 尝试这个 :
newList = [list(filter(lambda j:j!=0, i)) for i in myList]
OUTPUT : 输出 :
[[123, 345], [45], [67, 8, 5, 6, 7]]
您还可以通过列表理解来做到这一点:
cleaned = [ [e for e in row if e != 0] for row in myList ]
You just need to wrap filter, not the whole statement: 您只需要包装过滤器,而不是整个语句:
myList = [list(filter(lambda j:j!=0,myList[i]) for i in range(len(myList))]
Also, you can skip the index, and iterate by lists in myList
: 另外,您可以跳过索引,并通过myList
的列表进行myList
:
myList = [list(filter(lambda j:j!=0, inner_list) for inner_list in myList]
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