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如何在PHP类中创建关联数组

[英]How to create associative array in PHP Class

This is my language class. 这是我的语言课。 Is it possible to create array as below? 是否可以如下创建数组? I tried but my compiler is throwing error. 我尝试过,但是我的编译器抛出错误。 If its outside class i can create that array. 如果它的外部类,我可以创建该数组。 But why cant i do the same from within class 但是为什么我不能在课堂上做同样的事情

Does not work 不起作用

class Language{
    private $LANG = array();

    /*
    ERROR CODE
    1   DATABASE
    2   EMPTY USERNAME AND PASSWORD
    */

    //1   DATABASE
    $LANG[1]["TITLE"] = "DATABASE CONNECTION ERROR";
    $LANG[1]["MESSAGE"] = "PLEASE CONTACT YOUR ADMISTRATOR";

    //2   EMPTY USERNAME AND PASSWORD
    $LANG[2]["TITLE"] = "LOGIN ERROR";
    $LANG[2]["MESSAGE"] = "INVALID USERNAME OR PASSWORD";

    //3   EMPTY QUERY ERROR
    $LANG[3]["TITLE"] = "ERROR";
    $LANG[3]["MESSAGE"] = "UNABLE TO COMMUNICATE WITH SERVER";
}

It works 有用

    private $LANG = array();

    /*
    ERROR CODE
    1   DATABASE
    2   EMPTY USERNAME AND PASSWORD
    */

    //1   DATABASE
    $LANG[1]["TITLE"] = "DATABASE CONNECTION ERROR";
    $LANG[1]["MESSAGE"] = "PLEASE CONTACT YOUR ADMISTRATOR";

    //2   EMPTY USERNAME AND PASSWORD
    $LANG[2]["TITLE"] = "LOGIN ERROR";
    $LANG[2]["MESSAGE"] = "INVALID USERNAME OR PASSWORD";

    //3   EMPTY QUERY ERROR
    $LANG[3]["TITLE"] = "ERROR";
    $LANG[3]["MESSAGE"] = "UNABLE TO COMMUNICATE WITH SERVER";

First. 第一。 You can't have a code in the class definition outside of method. 在方法之外的类定义中不能包含代码。 You need to wrap it in a method. 您需要将其包装在一个方法中。

Second. 第二。 If you want to operate on class instance's property you have to use the this-> keyword to indicate that. 如果要对类实例的属性进行操作,则必须使用this->关键字进行指示。

So your code can look like: 因此您的代码如下所示:

class Language
{
    private $LANG = array();

    function __construct()
    {
        /*
        ERROR CODE
        1   DATABASE
        2   EMPTY USERNAME AND PASSWORD
        */

        //1   DATABASE
        $this->LANG[1]["TITLE"] = "DATABASE CONNECTION ERROR";
        $this->LANG[1]["MESSAGE"] = "PLEASE CONTACT YOUR ADMISTRATOR";

        //2   EMPTY USERNAME AND PASSWORD
        $this->LANG[2]["TITLE"] = "LOGIN ERROR";
        $this->LANG[2]["MESSAGE"] = "INVALID USERNAME OR PASSWORD";

        //3   EMPTY QUERY ERROR
        $this->LANG[3]["TITLE"] = "ERROR";
        $this->LANG[3]["MESSAGE"] = "UNABLE TO COMMUNICATE WITH SERVER";
    }

    function getData()
    {
        return $this->LANG;
    }
}

$lang = new Language();
var_dump($lang->getData());

You can read more about it in the documentation: https://www.php.net/manual/en/language.types.object.php 您可以在文档中阅读有关它的更多信息: https : //www.php.net/manual/zh/language.types.object.php

EDIT: Demo here https://3v4l.org/qVtD9 编辑:此处的演示https://3v4l.org/qVtD9

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