[英]Pandas replace part of string with values from dictionary
I would like to replace the words in my dataframe 我想替换数据框中的字词
df = pd.DataFrame({"Text": ["The quick brown fox jumps over the lazy dog"]})
which match the keys in the following dictionary 匹配以下字典中的键
dic = {"quick brown fox": "fox",
"lazy dog": "dog}
with their values. 与他们的价值观。
The expected outcome is 预期的结果是
Text
0 The fox jumps over the dog
I tried the following code but there is no change to my df. 我尝试了以下代码,但我的df没有变化。
df["Text"] = df["Text"].apply(lambda x: ' '.join([dic.get(i, i) for x in x.split()]))
I would like to know if there is any way to do this? 我想知道是否有任何方法可以做到这一点? I have a dataframe with around 15k rows.
我有一个约15k行的数据框。
Thanks in advance! 提前致谢!
Use .replace
with regex=True
将
.replace
与regex=True
Ex: 例如:
import pandas as pd
dic = {"quick brown fox": "fox", "lazy dog": "dog", "u": "you"}
#Update as per comment
dic = {r"\b{}\b".format(k): v for k, v in dic.items()}
df = pd.DataFrame({"Text": ["The quick brown fox jumps over the lazy dog"]})
df["Text"] = df["Text"].replace(dic, regex=True)
print(df)
Output: 输出:
Text
0 The fox jumps over the dog
You could use a for
loop with Series.str.replace
: 您可以在
Series.str.replace
使用for
循环:
for pat, repl in dic.items():
df.Text = df.Text.str.replace(pat, repl)
[out] [出]
Text
0 The fox jumps over the dog
You can use the replace
method of the str
accessor along with a regex generated from the keys of dic
: 您可以将
str
访问器的replace
方法与从dic
的键生成的regex一起使用:
df['Text'].str.replace('|'.join(dic), lambda string: dic[string.group()])
Output: 输出:
0 The fox jumps over the dog
Name: Text, dtype: object
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