SQL查询以在一段时间内每天选择最小值和最大值

Question

I would like to select all the rows that contain either min or max datetime values for each equipment_id , for every day included in the period.

The code below selects the min and max datetime values for each equipment_id over the entire period. What can/should I change to reach desired select results?

Note: the values enclosed in braces in the code snippet represent dynamic values.

select *
from equipment
where created_at in (select min(created_at)
                     from equipment
                     where created_at >= {start_datetime} and created_at < {end_datetime}
                     group by equipment_id
                    ) or
      created_at in (select max(created_at)
                     from equipment
                     where created_at >= {start_datetime} and created_at < {end_datetime}
                     group by equipment_id
                    )
order by account, equipment_id, created_at asc;

Answer 1

Use window functions:

select e.*
from (select e.*,
             min(e.created_at) over (partition by e.equipment_id, to_date(e.created_at)) as min_ca,
             max(e.created_at) over (partition by e.equipment_id, to_date(e.created_at)) as max_ca
      from equipment e
     ) e
where e.created_at in (min_ca, max_ca)
order by account, equipment_id, created_at asc;

Answer 2

Use to_date to extract date from datetime value. Then, join on an aggregate query:

with agg as
  (select to_date(created_at) as created_date, 
          equipment_id,
          min(created_at) as min_created_at,
          max(created_at) as max_created_at
   from equipment
   group by to_date(created_at),
            equipment_id
  )

select e.*
from equipment e
left join agg
   on e.equipment_id = agg.equipment_id
   and to_date(e.created_at) = agg.created_date

where e.created_at in (agg.min_created_at, 
                       agg.max_created_at)