使用Python工作表中的名称映射，借助Python脚本重命名文件夹中的文件名

Question

There are many CSV files in a folder which I want it to be renamed. There is an excel sheet which contains name of files to be renamed to folder.

The files in folder are named as

TestData_30April.csv
TestData_20April.csv
TestData_18April.csv etc

while the excel sheet contains the name as

0.25-TestData_30April
0.98-TestData_20April
0.33-TestData_20April etc

Also first row in the excel sheet contains Header name while row 2 on wards contains the file name to be renamed.

My Aim is to rename

TestData_30April.csv to 0.25-TestData_30April.csv similarly for all other files as well.

Here is the Code:

import os
import xlrd

#Excel Sheet containing name of files to be renamed in that folder
path="C:\\Users\\Desktop\\Test_Data\\Test_Summary.csv"

#Folder Containg all orginal file names
dir = "C:\\Users\\Desktop\\Wear_Data"

wb = xlrd.open_workbook(path) 
sheet = wb.sheet_by_index(0)
sheet.cell_value(0, 0)

#In excel sheet column X or col_values(23) contains the file name to be renamed
print(sheet.col_values(23))  

list_of_filename_in_folder = [] # name of the files in the folder
list_of_filename_in_excel = [] #name of the files in excel
path_to_folder = ''  # base path of folder  
for name in list_of_filename_in_excel:
    excel_file_name = os.path.join(path_to_folder, name,'.csv')
    dir_file_name = os.path.join(path_to_folder,name.split('-')[1],'.csv' )
    if os.path.exists(dir_file_name):
        print('changing file name {} to {}'.format(name.split('-')[1],name))
        os.rename(dir_file_name, excel_file_name)
    else:
        print('no file {} with name found in location'.format(name.split('-')[1]+'.csv')








Here is the error
    dir_file_name = os.path.join(path_to_folder,name.split('-')[1],'.csv')

IndexError: list index out of range

Answer 1

try below code:

for name in list_of_filename_in_excel:
    excel_file_name = os.path.join(path_to_folder, name,'.csv')
    newname = name
    if '-' in name:
        newname = name.split('-')[1]
    dir_file_name = os.path.join(path_to_folder,newname,'.csv' )

    if os.path.exists(dir_file_name):
        print('changing file name {} to {}'.format(newname,name))
        os.rename(dir_file_name, excel_file_name)
    else:
        print('no file {} with name found in location'.format(newname+'.csv')