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为什么在使用语义UI的搜索组件进行响应时,合成事件上没有`keyCode`值?

[英]Why is there no `keyCode` value on the synthetic event in react using Semantic UI's Search component?

I have created a simple Search with Semantic UI's Search Component like this: 我已经使用语义UI的搜索组件创建了一个简单的搜索,如下所示:

<Search
    value={searchString}
    onSearchChange={onSearchChange}
    showNoResults={false}
    size="massive"
    placeholder="eg. Huberdo"
    input="text"
  />

This is my onSearchChange func: 这是我的onSearchChange函数:

const onSearchChange = (e, data) => {
console.log(e.keyCode);
if (e.keyCode === 13) {
  submit();
}
setSearchString(e.target.value);
};

Here is a minimum example of my problem. 这是我的问题的最小示例。 https://codesandbox.io/s/blue-leaf-7mzvo?fontsize=14 https://codesandbox.io/s/blue-leaf-7mzvo?fontsize=14

The Problem: 问题:

When I console log the event, I can't find any information about the keyCode that was pressed. 当我在控制台上记录事件时,找不到与所按下的keyCode有关的任何信息。 e.keyCode is undefined as is e.charCode . e.keyCode未定义的是e.charCode

I need this so I can submit the search when the user hits enter. 我需要这样做,因此我可以在用户点击Enter时提交搜索。

Where is the keyCode hidden? keyCode隐藏在哪里?

According to the Semantic UI Doc's the func gets passed in a normal synthetic react event. 根据语义UI Doc的说法,函数是在正常的合成React事件中传递的。 e.target.value is working as expected. e.target.value运行正常。

You can do this by adding an onKeyDown prop: 您可以通过添加onKeyDown道具来做到这一点:

import React, { useState } from "react";
import ReactDOM from "react-dom";
import { Search } from "semantic-ui-react";

import "./styles.css";

function App() {
  const [searchString, setSearchString] = useState("");

  const handleEnter = e => {
    if (e.keyCode === 13) {
      submit();
    }
  };

  const onSearchChange = (e, data) => {
    setSearchString(e.target.value);
  };

  const submit = () => {
    console.log("submitted");
  };

  return (
    <Search
      value={searchString}
      onSearchChange={onSearchChange}
      showNoResults={false}
      size="massive"
      placeholder="eg. Huberdo"
      input="text"
      onKeyDown={handleEnter}
    />
  );
}

const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);

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