jq 1.5从另一个数组中的数组打印项目

Question

Incoming json file contains json array per row eg:

["a100","a101","a102","a103","a104","a105","a106","a107","a108"]
["a100","a102","a103","a106","a107","a108"]
["a100","a99"]
["a107","a108"]

a "filter array" would be ["a99","a101","a108"] so I can slurpfile it

Trying to figure out how to print only values that are inside "filter array", eg the output:

["a101","a108"]
["a108"]
["a99"]
["a108"]

Answer 1

You can port IN function from jq 1.6 to 1.5 and use:

def IN(s): any(s == .; .);
map(select(IN($filter_array[])))

Or even shorter:

map(select(any($filter_array[]==.;.)))

Answer 2

I might be missing some simpler solution, but the following works :

map(select(. as $in | ["a99","a101","a108"] | contains([$in])))

Replace the ["a99","a101","a108"] hardcoded array by your slurped variable.

You can try it here !

Answer 3

In the example, the arrays in the input stream are sorted (in jq's sort order), so it is worth noting that in such cases, a more efficient solution is possible using the bsearch built-in, or perhaps even better, the definition of intersection/2 given at https://rosettacode.org/wiki/Set#Finite_Sets_of_JSON_Entities

For ease of reference, here it is:

def intersection($A;$B):
  def pop:
    .[0] as $i
    | .[1] as $j
    | if $i == ($A|length) or $j == ($B|length) then empty
      elif $A[$i] == $B[$j] then $A[$i], ([$i+1, $j+1] | pop)
      elif $A[$i] <  $B[$j] then [$i+1, $j] | pop
      else [$i, $j+1] | pop
      end;
  [[0,0] | pop];

Assuming a jq invocation such as:

jq -c --argjson filter '["a99","a101","a108"]' -f intersections.jq input.json

an appropriate filter would be:

($filter | sort) as $sorted
| intersection(.; $sorted)

(Of course if $filter is already presented in jq's sort order, then the initial sort can be skipped, or replaced by a check.)

Output

["a101","a108"]
["a108"]
["a99"]
["a108"]

Unsorted arrays

In practice, jq's builtin sort filter is usually so fast that it might be worthwhile simply sorting the arrays in order to use intersection as defined above.