随机指定文件夹中的文件名

Question

I have a specific folder which contains files and I need to randomize their names. Folder location needs to be able to be changeable and file names should contain 6 - 10 characters from a - z. How can I do this in python?

Answer 1

 import string, random
 from random import randint
 import os, sys

 path = raw_input("Location of directory")
 nameDirectory = ''.join(random.choice(string.ascii_lowercase) for _ in xrange(randint(6, 10)))
 pathDir = path + "/" + nameDirectory
 print "name of new directory with path " + pathDir
 os.mkdir( pathDir, 0755 )

Also in script you can read the permission for new created directory.

Answer 2

I was going to offer up pretty much the same answer as @user1929959's fine offering. The only difference is that my version varied the number of letters between 6 and 10. So the actual line that produced the names in my version was:

newname = ''.join([choice(ascii_lowercase) for _ in range(randint(6, 10))])

UPDATE: I realize that maybe you wanted something different than the other answer...you wanted existing files renamed. Here's the code that does that, except that I just print the rename operation rather than doing it so I can see what would happen without having to keep renaming back the files during testing. You can change the print() line to a os.rename() call to actually do the renaming.

from string import ascii_lowercase
from random import choice, randint, random
import os

def randomize_files(dir):
    for f in os.listdir(dir):
        path = os.path.join(dir, f)
        if os.path.isfile(path):
            newpath = os.path.join(dir, ''.join([choice(ascii_lowercase) for _ in range(randint(5, 8))]))
            # os.rename(path, newpath)
            print("rename {} to {}".format(path, newpath))

randomize_files("/tmp/tset21")

Result for my test dir with 4 files in it:

rename /tmp/tset21/bb to /tmp/tset21/idqjp
rename /tmp/tset21/dd to /tmp/tset21/zlyeflfa
rename /tmp/tset21/aa to /tmp/tset21/jjbvrm
rename /tmp/tset21/cc to /tmp/tset21/pkywyyz