检查int在范围内时，无法将void转换为int

Question

I'm using this code and it's giving me an error saying that it cannot convert void to int:

    private static int aBtn;
    public static int ABtn
    {
        get => aBtn;
        set => aBtn = CheckArgumentRange(nameof(value), value, 0, 5);
    }

    internal static void CheckArgumentRange(
        string paramName, int value, int minInclusive, int maxInclusive)
    {
        if (value < minInclusive || value > maxInclusive)
        {
            throw new ArgumentOutOfRangeException(paramName, value,
                $"Value should be in range [{minInclusive}-{maxInclusive}]");
        }
    }

Can anyone see what's wrong and why it's giving this error?

Answer 1

You will need to return the value if it's not out of range. Otherwise the set doesn't receive an int.
So simply add return value; after your if and you should be good.

Edit: and of course change the return type from void to int.

    private static int aBtn;
    public static int ABtn
    {
        get => aBtn;
        set => aBtn = CheckArgumentRange(nameof(value), value, 0, 5);
    }

    internal static int CheckArgumentRange(
        string paramName, int value, int minInclusive, int maxInclusive)
    {
        if (value < minInclusive || value > maxInclusive)
        {
            throw new ArgumentOutOfRangeException(paramName, value,
                $"Value should be in range [{minInclusive}-{maxInclusive}]");
        }

        return value;
    }