如何在Oracle SQL中使用REGEX检索十进制后的特定字符？

Question

I'm using RegEx in a View in Oracle 11g and I need to display certain codes that have an 'S' in the 8th position.

Using https://regexr.com/2v41h ,

I was able to display these results with REGEXP_SUBSTR(code, '\\S{8}') Y38.9X2S Y38.9X2D Y38.9X2A Y38.9X1S

My issue is that I need to return only the values that have an 'S' in the last position which is the 8th position counting the decimal. What expression should I use?

Example: Y38.9X2S Y38.9X1S

I have tried: REGEXP_SUBSTR(code, '\\b[S]*[8]\\b') AS CODE

Thank you in advance for your help.

Answer 1

I am thinking:

select substr(code, -8)
from t
where code like '%_______S'

If the code is always long enough, just use '%S' .

Or, as a case expression:

select (case when code like '%_______S' then substr(code, -8) end)

You will need regular expressions if code has other characters but they may not be necessary.