在View CodeIgniter中加载视图
[英]Load View in View CodeIgniter
问题描述
I want to load a view which come from logical statement (in controller ) IN a view . 
我想在view中加载来自逻辑语句（在controller ）的view 。 Simply like this 就像这样
Controller 调节器
public function index(){
$this->lib();
$this->view('main');
}
public function lib(){
if(TRUE){
// $this->view('something1') in $this->view('main')
}
else{
// $this->view('something2') in $this->view('main')
}
}
** View ** **查看**
<html>
<body>
<!-- view from $this->view('main') -->
<!-- want to show view from lib() -->
</body>
</html>
How to show $this->view('something') get from lib() in $this->view('main') ? 如何显示$this->view('something')从$this->view('main') lib()获取？ Any idea ? 任何想法 ？
2 个解决方案
解决方案1
1 2019-05-21 04:40:35
The only way that I've found works is this: 我发现有效的唯一方法是：
Controller: 控制器：
public function index() {
$data['internal_view'] = $this->load->view('stmt', [], true);
$this->load->view('main', $data);
}
"main" View: “主”视图：
<html>
<body>
<?php echo $internal_view; ?>
</body>
</html>
Note: the 3rd param in view allows for the view to be returned as a string rather than automatically outputted to the browser. 注意： view的第三个参数允许视图以字符串形式返回，而不是自动输出到浏览器。 Because of this functionality, you can assign a view as a return string from another function and use it to generate internal_view or whatever you decide to call it. 由于此功能，您可以将视图分配为另一个函数的返回字符串，并使用它生成internal_view或您决定调用的任何内容。
解决方案2
0 2019-05-21 04:53:47
You could preserve the main view and also keep the lib conditional view and pass it to the main controller. 您可以保留主视图，还可以保留lib条件视图，并将其传递给主控制器。
Controller : 控制器：
public function index(){
$data['lib_view'] = $this->lib();
$this->view('main', $data);
}
public function lib(){
if(TRUE){
return $this->load->view('something1', true);
}
else{
return $this->load->view('something2', true);
}
}
'main' View : “主”视图：
<html>
<body>
<!-- view from $this->view('main') -->
<?php echo $lib_view ?>
</body>
</html>
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