将对象数组中两个属性的唯一值存储到单个数组中

Question

How to get unique values of requesterPractitionerId & performerOrganizationId. I need to stroe the unique values of requesterPractitionerId & performerOrganizationId in a single array.

[ 
    { 
        id: '1043120',
        requesterPractitionerId: '1043119',
    },
    { 
        id: '1043081',
        requesterPractitionerId: '1043080'
    },
    { 
        id: 'e1dceebe-c5ba-46a5-a63a-bff709896af4',
        requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
        performerOrganizationId: '05D0889009',
    },
    { 
        id: '2709842f-41e3-4193-8607-fc34d3d24ec1',
        requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
        performerOrganizationId: '05D0889009'
    } 
]

Expected Output:

1043119
1043080
e0a844e4-6c8a-489a-8bd6-1d62267d311e
05D0889009

I am new to Javascript and struggling with this for a couple of hours. Any help would be realy aapreciated.

Answer 1

Use Set , Array.reduce and Array.from

• Use reduce to create a set with unique values of the said fields
• Then convert the set to array using Array.from

 let arr = [{id:'1043120',requesterPractitionerId:'1043119'},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}]; let result = Array.from(arr.reduce((a,c) => { if(c.requesterPractitionerId) a.add(c.requesterPractitionerId); if(c.performerOrganizationId) a.add(c.performerOrganizationId); return a; }, new Set())); console.log(result); 

Answer 2

One solution is to use Array.reduce() to generate a new Set from the properties you need. After that, you can spread the set's items inside an array.

 const input = [{id:'1043120',requesterPractitionerId:'1043119'},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}]; let res = input.reduce((acc, o) => { if (o.hasOwnProperty("requesterPractitionerId")) acc.add(o.requesterPractitionerId); if (o.hasOwnProperty("performerOrganizationId")) acc.add(o.performerOrganizationId); return acc; }, new Set()) console.log([...res]); 

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Answer 3

You can use forEach to iterate data and then use Set to remove the duplicates

 let data = [{ id: '1043120', requesterPractitionerId: '1043119', }, { id: '1043081', requesterPractitionerId: '1043080' }, { id: 'e1dceebe-c5ba-46a5-a63a-bff709896af4', requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e', performerOrganizationId: '05D0889009', }, { id: '2709842f-41e3-4193-8607-fc34d3d24ec1', requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e', performerOrganizationId: '05D0889009' } ] let newArry = []; data.forEach(function(item) { newArry.push(item.requesterPractitionerId); if (item.hasOwnProperty('performerOrganizationId')) { newArry.push(item.performerOrganizationId) } }) let k = Array.from(new Set(newArry)); console.log(k) 

Answer 4

Really simple - Set and map , reduce and filter :

 const arr = [{id:'1043120',requesterPractitionerId:'1043119',},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}]; const res = [...new Set(arr.map(({ requesterPractitionerId, performerOrganizationId }) => [requesterPractitionerId, performerOrganizationId]).reduce((acc, curr) => acc.concat(curr)).filter(Boolean))]; console.log(res); 

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