使用Php编码到base64会产生与Python 3不同的结果

Question

I am trying to convert a code in Php to Python, it consists of encoding a variable obtained with the chr function with base64 using the base64_encode function.

Here is the code in Php:

$data = chr(ord('a')+ord('b'));
$data = base64_encode($data);
echo $data;

result:

ww==

Here is what I tried to do in Python:

from base64 import b64encode

data = chr(ord('a')+ord('b'))
data = b64encode(data.encode()) // data.encode() is mandatory or I get an error saying that b64encode require a bytes-like object
print(data)

result:

b'w4M='

Thank you for your help

Aymeric

Answer 1

I don't know if it's the real answer to the question, but the problem is that python string from version 3 are in unicode. so the php-code can be replaced:

<?php
$data = chr(ord('a')+ord('b'));
$data = utf8_encode($data);

echo base64_encode($data); //w4M=

or you can use https://www.php.net/manual/en/function.mb-chr.php for this

so for changing python code to work it as php - you need to encode data in latin-1:

from base64 import b64encode

data = chr(ord('a')+ord('b')).encode('latin-1')
data = b64encode(data)

print(data) # b'ww=='
print(data.decode()) # ww==