使用python将嵌套列表保存到新的较小列表中

Question

I have a list(thislist), i split it in smaller lists(nested) and i want to take each index of the nested list and save it in different list,array etc

thislist = [39.435138344488145, 22.73229454094485, 39.43684333469196, 22.73215634579526, 39.43681019007974, 22.731609175156223, 39.43507007579199, 22.731759378861057, 39.43511979394629, 22.732236812065707, 39.435138344488145, 22.73229454094485]

n = 2

def divide_chunks(l, n):
    for i in range(0, len(l), n):
        yield l[i:i + n]

x = list(divide_chunks(thislist, n))
print(x)

I expect the output to be like:

list1=[39.435138344488145, 22.73229454094485]
list2=[39.43684333469196, 22.73215634579526]
list3= [39.43681019007974, 22.731609175156223]
etc

Answer 1

Try this out-

chunks = [thislist[x:x+2] for x in range(0, len(thislist), 2)]
list_dict = {i: chunks[i] for i in range(0, len(chunks))}
g = globals()
for i in range(0, len(chunks)):
    g['list{0}'.format(i)] = list_dict[i]

This should give you your desired output! :)

Answer 2

I think this is what you want:

thislist = [39.435138344488145, 22.73229454094485, 39.43684333469196, 22.73215634579526, 39.43681019007974, 22.731609175156223, 39.43507007579199, 22.731759378861057, 39.43511979394629, 22.732236812065707, 39.435138344488145, 22.73229454094485]

n = 2

def divide_chunks(l, n):
    for i in range(0, len(l), n):
        yield l[i:i + n]

for index, x in enumerate(divide_chunks(thislist, n)):
    exec("list{} = x".format(index + 1))
try:
    print(list1)
except NameError:
    print("Not a valid list")

That being said you are better off just doing list indexing for most use cases. (Using exec and eval is usually not recommended).