在ruby> = 2.5.1 /> = rails 5中生成随机令牌
[英]Generate a random token in ruby >= 2.5.1 / >= rails 5
问题描述
I can see from here that has_secure_token can generate a random token for a new record in a (User) model. 
从这里可以看到has_secure_token可以为（用户）模型中的新记录生成随机令牌。 How can I simply generate a random token without needing to do it for a model? 如何简单地生成随机令牌而无需为模型做呢？ (ie suppose an app has no model(s) or to put it really simply, to run some (preferably very simple) method, and it should return a random string like pX27zsMN2ViQKta1bGfLmVJE （即，假设某个应用没有模型，或者说它很简单，可以运行某种方法（最好是非常简单）），并且它应该返回一个随机字符串，例如pX27zsMN2ViQKta1bGfLmVJE
I have tried gems SecureRandom and digest as recommended in other answers, but neither seems to bundle install successfully (the SO answers were oldish so perhaps those gems are deprecated?) - I'm using ruby 2.5.1 and rails 5.2.3 我已经按照其他答案中的建议尝试了宝石SecureRandom和digest ，但是似乎都没有成功捆绑安装（SO答案很旧，所以也许这些宝石已被弃用？）-我使用的是ruby 2.5.1和rails 5.2.3
My goal is simply to generate tokens to use as keys for an API, so I essentially just need randomly generated strings that are safe to use in urls, perhaps a method that I can specify the length of the token (but I'll take what I can get for now!) 我的目标只是生成令牌以用作API的键，因此，我基本上只需要可以在url中安全使用的随机生成的字符串，也许我可以指定令牌的长度（但是我会选择我现在可以得到！）
1 个解决方案
解决方案1
2 已采纳 2019-05-26 06:53:02
Just use SecureRandom . 只需使用SecureRandom 。 It's not a gem that you have to install. 它不是必须安装的宝石。 It's built into Ruby: 它内置在Ruby中：
⇒ ruby -v
ruby 2.5.1p57 (2018-03-29 revision 63029) [x86_64-darwin18]
⇒ irb
2.5.1 :001 > require 'securerandom'
=> true
2.5.1 :002 > SecureRandom.hex(32)
=> "89d45edb28859a905672b707c8f7599f766d12074584ef48a997230dfc0e0998"
2.5.1 :003 > SecureRandom.base64(12)
=> "KaZbhQ7o7U/f9pMs"
2.5.1 :004 > SecureRandom.uuid
=> "ade17ef5-0943-4c70-b417-df7c96c198cd"
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