Oracle：使用where子句按月选择日期

Question

I came across a problem that in selecting the date for current desired month and year. I tried the 2 statements shown below but failed to execute the query

select to_char(sysdate, 'Month') from income

select * from income where to_char(sysdate,month) = 'feb'

Update

But after researching and learning more in depth on oracle docs website. What i came out with is to use "between" clause. Specifying the first day and last day of the month . Doing so, it will execute the desired month/year

For an example

SELECT column_name
FROM table_name where column_name = (Your own value) AND
column_date >= to_date('01/02/2012', 'dd/mm/yyyy')
and column_date <  to_date('01/03/2012', 'dd/mm/yyyy')  

I hope this help :)

Answer 1

Are you after something like:

select *
from   income
where  <date_column> >= to_date('01/05/2019', 'dd/mm/yyyy')
and    <date_column> <  to_date('01/06/2019', 'dd/mm/yyyy')

(replacing <date_column> with the name of the date column in your income table that you want to filter on)?

Answer 2

I think you can use the following query:

select *
from   income
where  to_char(<date_column>,'MON-RRRR') = 'MAY-2019';

Answer 3

If you want to pass in a string like 'May 2012' , then I would recommend:

select i.*
from income i
where i.datecol >= to_date('May 2012', 'Mon YYYY') and
      i.datecol < to_date('May 2012', 'Mon YYYY') + interval '1' month;

That said, I think your application should turn the string value into a date range and you should use that range in your query:

select i.*
from income i
where i.datecol >= :datestart
      i.datecol < :dateend + interval '1 day';

I strong encourage you to avoid between with dates, particularly in Oracle. The date data type has a built-in time component, and that can throw off the comparisons.