在C ++中使用递归时无法传递二维数组

Question

I saw an answer in stackoverflow regarding how to pass a 2d-array in a function there are 3 or more methods given when I tried one of them it worked just fine. But when I'm trying to use that method in backtracking it is giving me an error.

I tried declaring it globally but I want to learn how to use it this way

#include<bits/stdc++.h>
using namespace std;

int callAgain(int,int);
int call(int,int);

int call(int arr[][5],int n)
{
  if(n==1)
    return 0;

  cout<<"anything";

  callAgain(arr,n-1);     //getting error here.

  return 0;
 }
int callAgain(int arr[][5],int n)
{
  call(arr,n);
  return 0;
 }
int main(){

int arr[5][5];
memset(arr,0,sizeof(arr));
call(arr,5);

return 0;
}

error: invalid conversion from int(*)[5] to int [-fpremissive]

Answer 1

Your forward declarations for call and callAgain promise that the first argument will be an int , but then when you implement them you say the first argument is a 2D array.

Compilers don't appreciate being lied to...