我想在第一张表中获取不在第二张表中的行

Question

I have a table, let's call it fees , and two other tables, let's call them transactions and breakdowns .

transactions table saves the general summary of payments received while breakdowns table saves the breakdown of the payments.

breakdowns table looks something like this

id | transaction_id | fee_id

and fees table looks something like this

id | amount | description

I'd like to fetch the fees in fees table that do not have records in breakdowns table based on the transaction_id

SELECT * FROM fees LEFT JOIN breakdowns ON (fees.id = breakdowns.fee_id) 
WHERE breakdowns.transaction_id = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxx';

The code above returns empty rows

Answer 1

Use not exists :

SELECT f.*
FROM fees f
WHERE NOT EXISTS (SELECT 1
                  FROM breakdowns b
                  WHERE b.fee_id = f.id AND
                        b.transaction_id = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
                 );

You can use a LEFT JOIN as well, moving the condition on breakdowns to the ON clause:

SELECT *
FROM fees f LEFT JOIN
     breakdowns b
     ON b.fee_id = f.id AND  
        b.transaction_id = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxx';

However, I think NOT EXISTS more directly captures the logic you want. Also, I see no reason to return the NULL values for the columns in breakdowns .

Answer 2

try this

$data['showrecord'] = DB::table('fees')
           ->where('breakdown.transaction_id',"=",'xxxxx')
           ->leftjoin('breakdown', 'breakdown.fee_id', '=', 'fees.id')
           ->get();